Star Time:7:30 A.M Elapsed Time:2 hours, 20 minutes End Time is
1 answer:
You might be interested in
Let's first rewrite it in vertex form.
Start by completing the square.
y = x² + 4x + 4 - 4 - 1
y = (x + 2)² - 5
(x + 2)² = y + 5
Now, 4a = 1; a =
So, the vertex form is (x + 2)² = 4()(y + 5)
So, we know that the vertex is at (-2, -5).
Since it's a concave up parabola, we just have to change the y-value to find the focus.
∴ F(-2, -5 +)
F(-2,
)
Start by completing the square.
y = x² + 4x + 4 - 4 - 1
y = (x + 2)² - 5
(x + 2)² = y + 5
Now, 4a = 1; a =
So, the vertex form is (x + 2)² = 4(
So, we know that the vertex is at (-2, -5).
Since it's a concave up parabola, we just have to change the y-value to find the focus.
∴ F(-2, -5 +
F(-2,
Answer:
Group A has greater variability
Step-by-step explanation:
Group A: 80, 100, 190, 110, 70, 90, 130
The variability of group A data :
Taking the range :
Maximum = 190 ; Minimum = 70
Range = Maximum - Minimum ; 190 - 70 = 120
Group B : 50, 110, 100, 120, 107, 140, 150
The variability of group B data :
Taking the range :
Maximum = 150 ; Minimum = 50
Range = Maximum - Minimum ; 150 - 50 = 100
Hence, Group A has greater variability
