Answer:
8
Step-by-step explanation:
f(x) = (x+2)(x-2)
Substituting x=1 into f(x):
f(1) = 3*-1
= -3
Since -2 & 2 touch the x-axis, 1 has a negative y value, 2 has a y value of 0, and all values from 2, are positive.
Hence,
3, 4, 5, 6, 7, 8, 9, 10 are all positive. Therefore, the answer is 8
This can be confirmed with a graph, as attached below.
<em>Feel free to mark this as brainliest! :D</em>
The numerators in each term are consecutive integers ≥ 6. If n = 1 refers to the first term, then the numerator of the n-th term would be n + 5.
The denominators are consecutive odd integers ≥ 7. Odd numbers take the form 2k - 1, where k is any integer, and 2k - 1 = 7 when k = 4. But we want our sequence to start at n = 1, so we replace k here with n + 3. Then the denominator of the n-th term would be 2 (n + 3) - 1, or 2n + 5.
The odd-indexed terms are negative, while the even-indexed terms are positive. We can account for the sign of the term by multiplying by (-1)ⁿ.
Taking everything together, it follows that the n-th term in the sequence is
Answer:
c. 0.0498
Step-by-step explanation:
First of all, let us find the number of four digit numbers possible.
There are 4 digits and let us have a look at the possibility of each digit.
Number of possible options for Unit's digit = 10
Number of possible options for ten's digit = 10
Number of possible options for hundred's digit = 10
Number of possible options for thousand's digit = 9 (because 0 can not be there to make it a 4 digit number)
Total number of possible outcomes =
As per the given condition, unit's digit is 7.
So, number of possible options for unit's digit = 1
Number of possible options for thousand's digit = 8 (7 and 0 can not be there to make it a 4 digit number)
Number of possible options for hundred's digit = 8 (7 and one digit used in thousand's place can not be there)
Number of possible options for ten's digit = 7 (7, two digits used at thousand's and hundred's places)
Number of possible outcomes as per given conditions =
Formula for probability of an event E can be observed as: