We know that
P = A/D
Where,
P = monthly payments,
A = Total amount =$1,000,000
![D=[(1+r/12) ^{12*t}-1]/[(r/12)*(1+r/12)^{12*t}]](https://tex.z-dn.net/?f=D%3D%5B%281%2Br%2F12%29%20%5E%7B12%2At%7D-1%5D%2F%5B%28r%2F12%29%2A%281%2Br%2F12%29%5E%7B12%2At%7D%5D%20%20)
in this problem
t=30 years
r=8%----> 0.08
![D=[(1+0.08/12) ^{12*30}-1]/[(0.08/12)*(1+0.08/12)^{12*30}] =136.2835](https://tex.z-dn.net/?f=D%3D%5B%281%2B0.08%2F12%29%20%5E%7B12%2A30%7D-1%5D%2F%5B%280.08%2F12%29%2A%281%2B0.08%2F12%29%5E%7B12%2A30%7D%5D%20%3D136.2835)
the answer is$7337.65
Answer:
You simply need to multiply
.
Multiply the numerators.
Multiply the denominators.
Simplify.
21, 23, 25 so 21 is the smallest odd number :)
Answer:
It would be the last option.
Answer:
Carl has 35 dimes and 90 quarters
Step-by-step explanation:
Let the number of quarters be q and the number of dimes be d
Total number of coins is 125;
Hence;
q + d = 125 •••••••••(i)
The total value of quarters present = q * 0.25 = 0.25q
The total value of dimes present = d * 0.1 = 0.1d
Adding both gives the total
0.25q + 0.1d =26 ••••••••(ii)
So we need to solve both equations simultaneously;
From i,
q = 125 - d
Substitute this into ii
0.25(125-d) + 0.1d = 26
31.25 -0.25d + 0.1d = 26
31.25 -26 = 0.25d -0.1d
5.25 = 0.15d
d = 5.25/0.15
d = 35
Recall; q = 125 - d = 125 -35 = 90
