Answer:
The symphonic choir can record a maximum of 14 songs.
Step-by-step explanation:
We know that the album cannot be more than 72 minutes long, and the jazz choir records a total of 
song minutes.
If we call 
the number of songs the symphonic choir records , and each song is 3.5 minute long, then the song minutes for the symphonic choir are 
; therefore, we have the inequality
<em> (this says the song minutes for jazz choir plus song minutes for symphonic choice cannot exceed 72 minutes )</em>
We solve this inequality by subtracting 21 from both sides and then dividing by 3.5:
The maximum integer value can take is 14; therefore, the maximum number of songs the symphonic choir can record is 14 songs.
Solve for y by simplifying both sides of the inequality, then isolating the variable.
Inequality Form:
y<−10 or 1<y<6
Interval Notation:
(−∞,−10)∪(1,6)
Two ways:
1) guess factors(trial and error)
2) use quadratic formula.
If you use this method then a = -3, b = -6 and c = -1
x = -b +/- [sqrt(b^2 -4ac)/2a]
substituting a, b, and c into our equation we get:
x = - (-6)+/- [sqrt ((-6)^2) - 4(-3)(-1))/2 (-3)]
x = + 6 +/- [sqrt (36 -4 (3)/-6)] if I didnt make a mistake in my signs
x = + 6 +/- [sqrt (36 -12)/-6)]
x = 6 +/- [sqrt (24)/-6] but sqrt 6 x sqrt of 4 = sqrt 24 hence
x = 6 +/- [ sqrt 6 x sqrt 4 /-6] that is:
x = 6 +/- [sqrt 6 x 2 /-6 ]
so x = 6 + [sqrt 6 x 2/-6] and x = 6 - [sqrt 6 x 2/-6]
Answer:
Step-by-step explanation:
All you need o divide 3,300 by 50
3300
÷ 50
--------------
66
so ever minute he would most likely type 66 words
X/5120=20/100
x/5120=1/5
5120/5=1024
1024+5120=6144
6144 is the answer.
