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3 years ago

Write a story about temperatures that this expression could represent: 27 + (-11)

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

7 0

Answer:

at noon the temperature was 27 degrees. At night, the sun went down and the temperature decreased by 11 degrees.

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Rewrite the quadratic function in vertex form.<br> Y=5x^2-10x+2

Natalka [10]

Answer:

y = 5x2 + 10x - 15

We want this in format y = a(x-h)2 + k

where the vertex will be at (h,k)

y = 5(x2+2x) - 15

Complete the square on x2+2x

y = 5(x2+2x+1) - 15 - 5

We subtract 5 at the end because we are actually adding 5(1) = 5

so we need to remove it also to keep the total equal

y = 5(x+1)2 - 20

The vertex is at (-1,-20)

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3 years ago

سا (a) From the definition of derivatives determine dy÷dx if y = -2÷x

harina [27]

Step-by-step explanation:

Given: $y = -\dfrac{2}{x}$

Derivative of a power function $x^n$ :

$\dfrac{d}{dx}(x^n) = nx^{n-1}$

Therefore,

$\dfrac{dy}{dx}=-2(-1)x^{-2} = \dfrac{2}{x^2}$

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3 years ago

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Molodets [167]

Answer:

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Step-by-step explanation:

I am not sure but I hope this helps some.

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3 years ago

Given: KLMN is a parallelogram, KA − angle bisector of ∠K LA − angle bisector of ∠L Prove: m∠KAL = 90°

sineoko [7]

Answer: angle KAL = 90°

Step-by-step explanation: The decision on a photo

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4 years ago

In a recent study on world happiness, participants were asked to evaluate their current lives on a scale from 0 to 10, where 0

uysha [10]

Answer:

a) A response of 8.9 represents the 92nd percentile.

b) A response of 6.6 represents the 62nd percentile.

c) A response of 4.4 represents the first quartile.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5.9

Standard Deviation, σ = 2.2

We assume that the distribution of response is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) We have to find the value of x such that the probability is 0.92

P(X < x)

$P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.92$

Calculation the value from standard normal z table, we have,

$P(z$

$\displaystyle\frac{x - 5.9}{2.2} = 1.405\\x = 8.991 \approx 8.9$

A response of 8.9 represents the 92nd percentile.

b) We have to find the value of x such that the probability is 0.62

P(X < x)

$P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.62$

Calculation the value from standard normal z table, we have,

$P(z$

$\displaystyle\frac{x - 5.9}{2.2} = 0.305\\x = 6.571 \approx 6.6$

A response of 6.6 represents the 62nd percentile.

c) We have to find the value of x such that the probability is 0.25

P(X < x)

$P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.25$

Calculation the value from standard normal z table, we have,

$P(z$

$\displaystyle\frac{x - 5.9}{2.2} = -0.674\\x = 4.4172 \approx 4.4$

A response of 4.4 represents the first quartile.

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3 years ago