W + 2 ≥ 3 solve for w

Please help, I I beg you please

Tatiana [17]

Answer:

The volume of the cube is $\mathit{\frac{27}{z^3x^{9}}}$ cu in.

Step-by-step explanation:

The Volume of a Cube

Let's have a cube of side length a. The volume of the cube is:

$V=a^3$

The cube of the image has a side length of

$\displaystyle a=\frac{3x^{-3}}{z}\ inches$

Simplifying the expression of the base by converting the negative exponent in the numerator to the denominator:

$\displaystyle a=\frac{3}{zx^{3}}\ inches$

Now find the volume:

$\displaystyle V=\left(\frac{3}{zx^{3}}\ inches\right)^3$

Applying the exponents:

$\displaystyle V=\frac{3^3}{z^3x^{9}}\ inches^3$

$\displaystyle V=\frac{27}{z^3x^{9}}\ inches^3$

The volume of the cube is $\mathbf{\frac{27}{z^3x^{9}}}$ cu in.

8 0

3 years ago

Plz gyz ineed the calculation

sergejj [24]

Answer:

Step-by-step explanation:

so he spends : 1/5 , 1/2 , 1/10.....common denominator of 10

1/5 + 1/2 + 1/10 = 2/10 + 5/10 + 1/10 = 8/10 = 4/5

so he spends 4/5 of his income.

that means he saves : 1 - 4/5 = 5/5 - 4/5 = 1/5 <==

8 0

2 years ago

You and your friend go to tacos Galore for lunch. You order 3 soft tacos and 4 burritos and your bill comes out to $18.00. Your

Korolek [52]

Answer:

Soft Tacos = 2

Burritos= 3

Step-by-step explanation:

You

3 x 2 = 6

18 - 6 = 12

12/4= 3

You spent 6$ on soft tacos and 12$ on burritos.

Your friend

2 x 2 = 4

10-4 = 6

6/2 = 3

Your friend spent 4$ on soft tacos and 6$ on burritos.

I hope I explained this well.

6 0

2 years ago

A sample of 38 observations is selected from one population with a population standard deviation of 3.4. The sample mean is 100.

kaheart [24]

Answer:

a. two-tailed test

b. reject H0 if Z>1.96 or Z<-1.96

c. Z = 1.73

d. we have failed to reject the null hypothesis

e. P-value = 0.0418

Step-by-step explanation:

We will use a Z test to resolve this, an it will be a two-tailed test because the hypothesis statements are not indicating a specific direction for the significant difference (H0 : μ1 = μ2 ; H1 : μ1 ≠ μ2), this also means that the significanclevel will be divided between the both tails (2.5% en each tail for the rejection regions). See attached drawing for reference.

We need to find our critical value:

Zα/2 = Z(0.05/2) = 0.025

If we look for 0.025 in a Z table we will find that the critical value is 1.96 to the right, and by symmetry -1.96 to the left. So our decision rule will be to reject H0 if Z>1.96 or Z<-1.96

The Z test will be done using the next equation:

Z = (x⁻1 - x⁻2) - (μ1 - μ2) / √( σ²1/n1 + σ²2/n2

Because we are testing the null hypothesis we know that μ1 - μ2 must be zero if they are supposed to be equal (H0 : μ1 = μ2), so we calculate as follows:

Z = (100.5 - 98.8) - (0) / √( (3.4)²/38 + (5.8)²/51 = 1.7/0.9817 = 1.73

Z<1.96, therefore we have failed to reject the null hypothesis

The P-value for this test would be represented by the probability of Z being greater than 1.73, so we can look for it in any Z table, finding that its value is 0.0418, and because P-value>0.025 we again confirm that we don't have evidence statistically significant to reject the null hypothesis