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liq [111]
3 years ago
12

A city police officer using radar checked the speed of 26 cars as they were travelling down a city street and the data is given

as below: 27 23 22 38 43 24 25 23 22 54 31 30 29 48 27 25 29 28 26 33 25 21 23 34 20 23 it is most like that the distribution of the dataset is ___________
Mathematics
1 answer:
pychu [463]3 years ago
5 0

Answer: The distribution of the data set is positively skewed.

<u>Explanation: </u>

In order to see whether the given data set is symmetric, positively skewed or negatively skewed, we will find the mean, median and mode of the given data set.

For symmetric distribution, Mean = Median=Mode

For positively skewed distribution, Mean > Median>Mode

For negatively skewed distribution, Mean < Median

The mean of the given data set is given below:

Mean = \frac{27+23+22+38+43+24+25+23+22+54+31+30+29+48+27+25+29+28+26+33+25+21+23+34+20+23}{26}

                =\frac{753}{26}

                =28.96

Now, the Median is:

To find the median we need to sort the data in ascending order as:

20,21,22,22,23,23,23,23,24,25,25,25,26,27,27,28,29,29,30,31,33,34,38,43,48,54

Median=\left(\frac{N+1}{2} \right)^{th} item

                   =\left(\frac{26+1}{2}\right)^{th} item

                   =13.5^{th} item

                   =26+0.5 \times (27-26)

                   =26.5

\therefore Median = 26.5

The mode is the most frequently occurring observation. Therefore the mode is:

Mode=23

Since the Mean >Median>Mode, therefore the distribution of the given data set is positively skewed.


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Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something.  If you have options that you're building toward, aim toward one of them.

{\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}    and   {\sec(\theta)}={\dfrac{1}{\cos(\theta)}

Recall the following reciprocal identity:

\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}

So, the original expression can be written in terms of only sines and cosines:

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\sin(\beta) *\dfrac{1 }{\cos(\beta) }

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Working toward one of the answers provided, this is the tangent function.


The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero.  However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to \tan(\beta).

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