Answer:
Results are below.
Step-by-step explanation:
Giving the following information:
Purchase price= $47,000
Salvage value= $2,900
Useful life= 5 years
<u>To calculate the annual depreciation, we need to use the following formula:</u>
Annual depreciation= (original cost - salvage value)/estimated life (years)
Annual depreciation= (47,000 - 2,900) / 5= $8,820
<u>The accumulated depreciation is calculated as follow:</u>
Accumulated depreciation= years of depreciation*annual depreciation
For year 4:
Accumulated depreciation= 8,820*4= $35,280
<u>Finally, the book value is:</u>
Book value= purchase price - accumulated depreciation
Year Annual depreciation Accumulated depreciation Book value
1 8820 8820 38180
2 8820 17640 29360
3 8820 26460 20540
4 8820 35280 11720
5 8820 44100 2900
Answer:
Figure 0 = 5 tiles
Figure 1 = 5 + 7 = 12 tiles
So, the equation is:
y = 7x + 5
because, it adds 7 tiles in every new figure.
<em>The</em><em> </em><em>equation</em><em> </em><em>is</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>7x</em><em> </em><em>+</em><em>5</em><em>.</em>
<em><u>Answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>y</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>7x</u></em><em><u> </u></em><em><u>+</u></em><em><u>5</u></em>
Well if you divide 2/3 by 1/2 you get 1/3
____________________
||||||||||||||||||||||||||___|___| |||||||||||||||||||||||||||=4/6
|||||||||||||=1/2 0f 2/3
0.005 would be 5/1000 because how I know if it is 10ths or 100ths or 1000ths I count all the number on the right side of the decimal, hoped this could help!
Answer:
7.5 hours
Step-by-step explanation:
Using the variable 't' for time, you can set up an equation to find out how long it will take the truck to catch up to the bus. Since the bus is traveling at 60mph and the truck is traveling 1 2/3 times faster, we need to first find the rate of the truck:
1

Using 't' and the knowledge that they will have traveled the same distance we the truck catches up to the bus and the fact that the truck left 3 hours later:
60t = 100(t - 3) or 60t = 100t - 300
Solve for 't': 60t - 100t = -300 or -40t = -300 so, t = 7.5 hours