Humans and Apes evolved separately from monkeys. Hope this helps.
Answer:
A.the flow of energy between organisms in an ecosystem
<span>The factor which is the least influential in affecting the biodiversity of wetlands is A. type of wetland. Regardless of its type, there will still be a lot of flora and fauna in a certain wetland. Other factors such as food resources, nutrients, and whether there is enough water are far more important for the existence of biodiversity than the type of wetlands.</span>
<h2>Development of Plant Needles</h2>
Explanation:
- Seed of pitch pine treated with colchicine delivered tetraploid seedlings which had thick and sporadic needles and less fortunate tallness and diameter growth than ordinary seedlings.
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In test of colchicine-initiated polyploidy in pines, researcher found that a significant number of the polyploid plants returned to a diploid development in light of the fact that the polyploid cells partitioned at a more slow rate and were overwhelmed by the more quickly developing diploid cells which encompassed them.
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The primary needles of both diploid and polyploid plants were more effective at low light intensity than secondary needles, and they had lower compensation points.
Answer/ Explanation:
a. The genotype of a homozygous white eyed long winged female would be Vg+Vg+XrXr. We denote the white allele as recessive (r) because the XY male only has one copy and yet has red eyes, so the red eye trait (R) must be dominant. A homozygous red eyed vestigial winged male would have be VgVgXRY. The possible gametes for the female are Vg+Xr only. For the male, the possible gametes are VgXR or VgY
The attached punnett square shows the results of the cross. The females will all be Vg+VgXRXr. The males will all be Vg+VgXRY (must inherit Y from father). That means they will all have normal length wings, the males will have white eyes and the females will have red eyes.
b. The F2 flies arise from intercrossing the F1, so the cross will be Vg+VgXRXr x Vg+VgXRY. The possible gametes for the mother are: Vg+XR, Vg+Xr, VgXR or VgXr. The possible gametes for the father are Vg+Xr
, Vg+Y
, VgXr
, VgY
. The attached punnet square shows this cross. The ratio of the phenotypes will be 6:6:2:2, or 3:3:1:1 (long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye), genotypes shown in the attachment.
c. F1 cross back to the mother would be Vg+VgXRY x Vg+Vg+XrXr. The genotypes are shown in the attached punnet square. The offspring will all be long-winged with white eyes. The F1 to the father would be Vg+VgXRXr x VgVgXRY. The ratio would be 3:3:1:1 long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye
