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marshall27 [118]
3 years ago
14

Find the principal. Annual rate of interest = 11 \%=11%equals, 11, percent Period = 3=3equals, 3 years Total interest = 825=825e

quals, 825 rupees Principal ==equals rupees
Mathematics
1 answer:
Andreyy893 years ago
6 0

Answer:

Principal = 2,500 rupees

Step-by-step explanation:

The interest or simple interest is the extra money gained on n invested amount of money yielding a certain percentage interest at a time (t) in years

The formula for simple interest is given as follows:

I = P × R × T

where:

I = interest = 825 rupees

P = principal

R = interest rate = 11% = 11/100 = 0.11

T = time = 3 years

∴ 825 = P × 0.11 × 3

825 = P × 0.33

P = 825 ÷ 0.33

P = 2,500 rupees

This means that 2,500 rupees was invested to saved to yield an interest of 825 rupees after 3 years at a rate of 11% per year

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Which is true about measurements in manufacturing? POSSIBLE ANSWERS: Product quality is not affected by size. Size is not advers
GaryK [48]

Answer:

A. Product quality is not affected by size.

Step-by-step explanation:

This statement is true because the quality of a product is not a measure of its size, which is a quantifiable factor. This means that we can have a very small-sized product which has very good quality. Size also depends on the product being manufactured. Quality is rather measured by how good the materials used in the production are.

If inferior materials are used in the production, then the product, no matter how small or big they are, would lack quality. To obtain a good and accurate measurement, a lot of time and energy should be invested.

5 0
3 years ago
The county fair charges $2.50 per ticket for the rides. Henry bought 15 tickets for the rides and spent a total of $55.50 at the
san4es73 [151]

Answer:

<em>(A)  $18</em>

<em>(B)   y=2.50x+18</em>

<em>(C)   Coefficient of x-term represents the cost for each ride ticket and constant term represents the cost of admission to the fair.</em>

Step-by-step explanation:

(A)

The county fair charges $2.50 per ticket for the rides and Henry bought 15 tickets for the rides.

So, the total cost of the 15 tickets will be:  (\$2.50*15)= \$37.50

He spent total $55.50 on ride tickets and fair admission.

So, the cost of admission to the fair will be:  (\$55.50-\$37.50)= \$18

(B)

If x represents the number of ride tickets and y represents the total cost, then the cost for x number of ride tickets is \$2.50x

So, the linear equation that can be used to determine the cost for anyone who pays for ride tickets and fair admission will be:   y= 2.50x+18

(C)

In the above linear equation, <u>coefficient of x-term is 2.50, which represents the cost for each ride ticket</u>.

And the <u>constant term is 18, which represents the cost of admission to the fair</u>.

4 0
3 years ago
I don’t know it tried solving it but couldn’t find it
Hitman42 [59]

8f - 25 = 47. Add 25 to both sides.

8f = 72. Divide each side by 8.

f = 9.

4 0
3 years ago
Read 2 more answers
What's the equivalent algebraic expression?
densk [106]
-10c+70, just distribute the the -10 to everything in the expression
3 0
3 years ago
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
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