Answer:
(1,1), (1,2), (2,1), (2,2)
Step-by-step explanation:
Answer:
expoential
Step-by-step explanation:
Answer:
We are given that angle AOB is a central angle of circle O and that angle ACB is a circumscribed angle of circle O. We see that AO ≅ BO because
✔ all radii of the same circle are congruent.
We also know that AC ≅ BC since
✔ tangents to a circle that intersect are congruent.
Using the reflexive property, we see that
✔ side CO is congruent to side CO.
Therefore, we conclude that △ACO is congruent to △BCO by the
✔ SSS congruence theorem.
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Step-by-step explanation:
The ratio of the perimeters = the scale
P₂ / P₁ = 6 / 4 = 3 / 2
The ratio of the areas = the square of the scale
A₂ / A₁ = (6 / 4)² = (3 / 2)² = 9 / 4
Same for the triangles:
P₂ / P₁ = 6 / 3 = 2
A₂ / A₁ = (6 / 3)² = (2)² = 4
Answer:
Given, 3x−2<2x+1
⇒3x−2x<1+2
⇒x<3orx∈(−∞,3)
The lines y=3x−2 and y=2x+1 both will intersect at x=3
Clearly, the dark line shows the solution of 3x−2<2x+1.
Step-by-step explanation: