The expression is
5x + 5y
We are to prove that it is an odd integer when x and y are integers of opposite parity
First, we can assume
x = 2a (even)
y = 2b + 1(odd)
subsituting
10(a + b) + 5
5 [(2(a + b) + 1]
The term
2(a + b) + 1 is odd and the result of an odd number multiplied by an odd number is odd
Step-by-step explanation:
To prove :
( 1 - sin x ) ( 1 + sin x ) = sec² x
LHS : -
( 1 - sin x ) ( 1 + sin x )
Formula / Identity : -
( a - b ) ( a + b ) = a² - b²
Here,
a = 1
b = sin x
( 1 - sin x ) ( 1 + sin x )
= 1 - sin² x
Identify : -
sin² θ + cos² θ = 1
cos² θ = 1 - sin² θ
Similarly,
1 - sin² x
= cos² x
= RHS
Hence verified.
The rest station is the midpoint of the given coordinates:
(-20+35)/2 , for the x value and (15+-12)/2 for the y value.
Coordinates of the rest station: (7.5, 1.5)
How far is the destination? Use the distance formula : D² = √(x1-x2) + (y1-y2)
(-55)² + (27)² = D² D = √3754 = 61.27
Answer:
Place value of 1st digit=7,000,000
,,. ,,,. ,,,. of 2nd digit= 70
Difference= 7,000,000-7
You get 6,999,930
This is your answer. If I'm right so,
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Answer:
3
Step-by-step explanation:
to find side length of squares take square root of areas
first square side length: 9
second square side length: 6
difference between 9 and 6 is subtraction, 9-6=3
