Answer:
8 is the number you seek
Step-by-step explanation:
Answer:
day 0, day 120
Step-by-step explanation:
You want to find the value of x that makes both y-values be the same:
y = y
30x +10 = -x^2 +150x +10
x^2-120x = 0 . . . . subtract the right side of the equation
x(x -120) = 0 . . . . . factor
Values of x that make this true are x=0 and x=120.
The same number of each car was sold on day 0 and day 120.
52 thousandths = 0.052
Move two decimal places to the right:
<h3><u>5.2 x 10⁻² ⇒ the scientific notation</u></h3>
Whenever a problem says "one number" and "another number" we can substitute x and y. for this we have x=2y+1 and xy=1. since we know the value of x (2y+1) we can substitute it for the other equation to get (2y+1)y=10. simplify to get 2y^2+y=10. from here you can do a few methods to solve this, but the simplest in my opinion is by factoring.
In order to factor it must be equal to 0, so we have 2y^2+y-10=0. We factor this and get y=5 (we also get y=-4 but it is an extraneous root). now we can plug that into either equation and find that x=2.
this means our two numbers are 5 and 2
Answer:
16
Step-by-step explanation:
4 goes into 64 evenly 16 times
