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AfilCa [17]
3 years ago
7

Solve for the value of X pleassee

Mathematics
1 answer:
bulgar [2K]3 years ago
3 0

Answer:

188

Step-by-step explanation:

SR and ST are equal in length so the arc SR and arc ST also have same measurement

since the perimeter of the circle is equal to 360 and arc RT is given as 64

x = (360 - 64) / 2

x = 188

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He difference of two numbers is 50. twice one number equals three times the other. find the numbers.
Juli2301 [7.4K]
X-y=50 and 2x=3y 
x=y+50 so 2(y+50) = 3y 

2y+100=3y
y=100

x-100=50
x=150

so our numbers are 150 and 100 

150-100=50 and 150 is 3*50 and 100 is 2*50 so fits all requirements!

hope this helps you! thank you!
6 0
3 years ago
HELP PLEASE!!!! I WILL GIVE 12 POINTS AND BRAINLIEST
Olenka [21]

Answer:

b

Step-by-step explanation:

5 0
3 years ago
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The number of calories Kira burns while riding a bike varies directly with the number of hours the bike is ridden. How many calo
Veseljchak [2.6K]

480 since 1 hour=60 minutes.  Look on the graph and you can see that the line looks like its 500 but since the answer choices dont say 500 it has to be 480 which is the closest


4 0
3 years ago
What is the vertex of this parabola? y= 2x² + 4x +5
uranmaximum [27]

Answer:

vertex = (- 1, 3 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = 2x² + 4x + 5 ← is in standard form

with a = 2, b = 4, then

x_{vertex} = - \frac{4}{4} = - 1

Substitute x = - 1 into the equation for corresponding value of y, that is

y = 2(- 1)² + 4(- 1) + 5 = 2 - 4 + 5 = 3

vertex = (- 1, 3 )

6 0
3 years ago
Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.
Lelechka [254]

Answer:

1) \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}} = 32

Step-by-step explanation:

1) \frac{(-2)^{-5}}{(-2)^{-10}}

Solving using exponent rule: a^{-m}=\frac{1}{a^m}

\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32

So, \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4}

Using the exponent rule: a^m.a^n=a^{m+n}

We have:

2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}

We also know that: a^{-m}=\frac{1}{a^m}

Using this rule:

2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}

So, 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2

Solving:

(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}

So, (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}}

We know that: a^{-m}=\frac{1}{a^m}

\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32

So, \frac{2}{2^{-4}} = 32

3 0
3 years ago
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