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balandron [24]
3 years ago
5

Create a Divisible application that displays a random integer between 1 and 100 and displays appropriate messages stating whethe

r the integer is even or odd, if the integer is divisible by 2, and if the integer is divisible by 3 when the Generate Number button is clicked. The application interface should look similar to:
Computers and Technology
1 answer:
mrs_skeptik [129]3 years ago
3 0

Answer:

function myFunction() {

 myNumber = Math.floor(Math.random() * 100) + 1 ;

 var values = ["Number is even", "Number is odd"] ;

 var stringNum = " ";

 if (myNumber % 2 === 0){

     stringNum += values[0];

 } else {

     stringNum += values[1];

 document.getElementById("demo").innerHTML = stringNum;

}

Explanation:

The javascript source code is used by the browser to make the web application interactive, making a clickable event for the button to generate an H1 header for the web page.

The myFunction is assigned to an onclick event of a html button tag to display if a random number between 1 and 100 is even or odd.

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Least common multiple of 78,90, and 140
Daniel [21]
The least common multiple (LCM) of 78, 90, and 140 is: 16,380

78 × 210 = 16,380
90 × 182 = 16,380
140 × 117 = 16,380
5 0
4 years ago
Read 2 more answers
Suppose you are given a string containing only the characters ( and ). In this problem, you will write a function to determine w
Whitepunk [10]

Answer:

Code is completed below

Explanation:

Source Code in Java:

class Parenthesis

{

boolean hasBalancedParentheses(String eq) //method to check and return if a set of parenthesis is balanced or not

{

int count=0; //to store count of current unclosed opening brackets

for(int i=0;i<eq.length();i++)

{

if(eq.charAt(i)=='(')

count++;

else if(eq.charAt(i)==')')

count--;

if(count<0) //if count falls below zero, there were more closing brackets than opening brackets till this point

return false;

}

if(count>0) //if count is still more than zero, there were less closing brackets than opening brackets

return false;

return true; //if program reaches this point, it has passed all the tests

}

public static void main(String args[])

{

//testing the function

Parenthesis ob=new Parenthesis();

System.out.println(ob.hasBalancedParentheses("()(()())((())())"));

System.out.println(ob.hasBalancedParentheses(")((()())(()))())"));

}

}

8 0
3 years ago
How to create a function, called separate_int_and_str, which takes in a list and separates out the integer values and strings in
gregori [183]

Answer:

program :

def separate_int_and_str(list_1):# function to seprate the list.

   str_list=[] #list to hold the

   int_list=[]#list which holds the integer value.

   for x in list_1: #for loop to extract the list.

       if(type(x)==str): #if condition to check the type of the element.

           str_list.append(x)#create a list for the string value.

       elif(type(x)==int): #check condition for th einteger value.

           int_list.append(x)#create a list for the integer value.

Explanation:

  • The above-defined function is written in the python language, which used the code to separate the list for integer and the string value.
  • There are two lists define in the function which holds the integer and the string value separately.
  • There is a 'for' loop which scans the element of the list and checks the list by the help of type function which tells the class of the element.
  • Then if the type function states that the element is from the strong class, it will assign the element on the string list otherwise it assigns the element in the integer list.
4 0
3 years ago
Social engineering attacks can be carried out:______.
Alik [6]
The answer most likely B NOT SURE )
3 0
3 years ago
You have been tasked with designing an Ethernet network. Your client needs to implement a very high-speed network backbone betwe
lorasvet [3.4K]

Answer:

A and C

Explanation:

From the above scenario, the Ethernet standards that meet the above guidelines are:

A. 1000BaseSX; and

C. 10GBaseSR.

Cheers

3 0
3 years ago
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