PLEASEEE HELP WILL GIVE BRAINLIEST
1 answer:
You might be interested in
f(x) = (x - )² -
the equation of a quadratic in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 )
then the x- coordinate of the vertex is
= -
f(x) = x² - 11x + 9 is in standard form
with a = 1, b = - 11 and c = 9
= -
=
substitute this value into the equation for y- coordinate
y = ()² - 11(
) + 9
= -
+
= -
f(x) = (x - )² -
← in vertex form
So this is trig, and when it comes to right (90°) triangles, it's imperative that you know:
SOH-CAH-TOA
Sine (x) = Opposite/Hypotenuse
Cosine (x) = Adjacent/Hypotenuse
Tangent (x) = Opposite/Adjacent
*hypotenuse is always the largest side, and the one opposite the 90° angle in right triangles
therefore we'll use SOH, because the opposite of x (O) and the hypotenuse (H) are given:
Sine (x) = Opposite/Hypotenuse
Sine (x) = 32/58 = 16/29 = 0.552
Sine (x) = 0.552
now we use something called arc-sine, or
it's basically a fancy function of most advanced calculators, so we'll plug it in as:
x = 33.49° --> answer B) is correct
SOH-CAH-TOA
Sine (x) = Opposite/Hypotenuse
Cosine (x) = Adjacent/Hypotenuse
Tangent (x) = Opposite/Adjacent
*hypotenuse is always the largest side, and the one opposite the 90° angle in right triangles
therefore we'll use SOH, because the opposite of x (O) and the hypotenuse (H) are given:
Sine (x) = Opposite/Hypotenuse
Sine (x) = 32/58 = 16/29 = 0.552
Sine (x) = 0.552
now we use something called arc-sine, or
it's basically a fancy function of most advanced calculators, so we'll plug it in as:
x = 33.49° --> answer B) is correct