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Dominik [7]
2 years ago
10

A: {-4, -2 -1, 2} B: {-4, 4} C: {-3, -2, 0, 2} D: {-4, -2, -1, 0, -2}

Mathematics
1 answer:
Temka [501]2 years ago
5 0

Answer:this is soooo compli

Step-by-step explanation:

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Slope intercept form of y-3=2/3(x+5)
Blizzard [7]

Answer:

It's already in slope intercept form

slope = 2/3

Intercept = (-5,3)

Step-by-step explanation:

3 0
3 years ago
plz help me suzy spent 6 7/8 days working on her English paper 3 1/6 days on her science project and 1 1/2 days studying for her
malfutka [58]

Answer:

English time + Math Time =  6 7/8 + 1 4/8 =  7 7/8+4/8  =  8 3/8

8 3/8 - Science time = difference =   8 3/8- 3 1/6 = 5 5/24

She spent 5 5/24 days more on her English and Math test than Science

Step-by-step explanation:


5 0
3 years ago
Write an equation of a line with the given slope and y-intercept. m = –2, b = 4
Verdich [7]
Y= -2x+4 m represents the x value and b the y intercept
4 0
3 years ago
Read 2 more answers
Use the quadratic formula to find both solutions to the quadratic equation given below x^2+6x=27
docker41 [41]

Answer:

x=3 or x=−9

Step-by-step explanation:

Step 1: Subtract 27 from both sides.

x2+6x−27=27−27

x2+6x−27=0

Step 2: Factor left side of equation.

(x−3)(x+9)=0

Step 3: Set factors equal to 0.

x−3=0 or x+9=0

x=3 or x=−9

Answer:

x=3 or x=−9

7 0
3 years ago
Read 2 more answers
Jacob transformed quadrilateral FGHJ to F'G'H'J'.
Rudik [331]

Answer:

A. Reflection across the line x = 1

Step-by-step explanation:  

Please find the attachment.

We have been given that Jacob transformed quadrilateral FGHJ to F'G'H'J'.  We are asked to find which transformation Jacob used to reflect FGHJ to F'G'H'J'.

Since we know that while reflecting a figure, the line of reflection will lie between the original figure and reflected figure. Each point of the reflected figure will have the same distance from the line of reflection as the corresponding point of the original figure.              

Now let us see our given choices one by one.

A. Reflection across the line x = 1.

Upon looking at point G and G' we can see that both points are equidistant (2 units) from the line x=1. Other corresponding points of both quadrilaterals are also equidistant from line x=1, therefore, Jacob used the reflection across the line x=1 to transform quadrilateral FGHJ to F'G'H'J'.

B. Reflection across the line y = 1 .      

If Jacob had reflected quadrilateral across line y=1, the points of quadrilateral F'G'H'J' will lie in second and third quadrant. We can see from our graph that F'G'H'J' lies in 1st quadrant, therefore, option B is not a correct choice.

C. Reflection across the line y-axis.

If Jacob had reflected quadrilateral across y-axis, the coordinates of points of quadrilateral F'G'H'J' will be G'(1,4), H'(1,2), J'(4,0) and F'(2,5). Therefore, option B is not a correct choice.

D.  Reflection across the x -axis.

If Jacob had reflected quadrilateral across x-axis, the points of quadrilateral F'G'H'J' will lie in third quadrant. We can see from our graph that F'G'H'J' lies in 1st quadrant, therefore, option D is not a correct choice.

3 0
3 years ago
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