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Levart [38]
3 years ago
15

How can you use regrouping to solve the equation 32-5 =

Mathematics
2 answers:
AveGali [126]3 years ago
6 0

Answer: 27

Step-by-step explanation:

you cross out the 3, taking 1 away, turning that 3 to a 2, then crossing out that 2 in 32, you get 12 by adding the 1 with the 2, if that makes sense (I haven't done regrouping in a while) 12-5 is 7, and then the 3, thats now a 2 in 32, 2-0= 2, so you'd result with 27 (if that makes sense at all, I hope it did)

Doss [256]3 years ago
3 0

Answer:

-5+32=27

Step-by-step explanation:

-5+32=27

Hope I helped!

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Answer:

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I am not sure if you wanted the answer. Sorry!

Step-by-step explanation:

Let's solve your equation step-by-step.

1/10 x + 5 = - 3x - 13 + 4x

Step 1: Simplify both sides of the equation.

1/10 x + 5 = - 3x - 13 + 4x

1/10 x + 5 = - 3x + - 13 + 4x

1/10 x + 5 = (<em>- 3x + 4x</em>) + (- 13)

1/10 x + 5 = <em>x</em> + - 13

1/10 x + 5 = x - 13

Step 2: Subtract x from both sides.

1/10 x + 5 - <em>x </em>= x - 13 - <em>x</em>

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Step 3: Subtract 5 from both sides

- 9/10 x + 5 - <em>5</em> = - 13 - <em>5</em>

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Step 4: Multiply both sides by 10/(- 9).

(<em>10/ - 9</em>) * (- 9/10 x) = (<em>01/ - 9</em>) * (- 18)

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Hope this helps!

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