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Levart [38]
3 years ago
15

How can you use regrouping to solve the equation 32-5 =

Mathematics
2 answers:
AveGali [126]3 years ago
6 0

Answer: 27

Step-by-step explanation:

you cross out the 3, taking 1 away, turning that 3 to a 2, then crossing out that 2 in 32, you get 12 by adding the 1 with the 2, if that makes sense (I haven't done regrouping in a while) 12-5 is 7, and then the 3, thats now a 2 in 32, 2-0= 2, so you'd result with 27 (if that makes sense at all, I hope it did)

Doss [256]3 years ago
3 0

Answer:

-5+32=27

Step-by-step explanation:

-5+32=27

Hope I helped!

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How do I do this?? Help!
Shkiper50 [21]

Hi there!

In order to use the elimination method, you have to create one variable that has the same coefficient. This is to be able to eliminate one variable and have a one variable equation (which you can then solve).

In your case, we'll have the "x" have the same coefficient by multiplying the top equation by 4 and the bottom equation by 2 :

4( -2x + 3y = -4) → -8x + 12y = -16

2( 4x - 2y = 16) → 8x - 4y = 32


Now that both of your equation have a variable with the same coefficient, you need to choose rather you need to add or subtract the equations in order to get rid of the variable (in this case we want to get rid of the "x").

In your case, you want to add both equation together which will give you :

8y = 16


Now that you only have one variable, all you need to do now is solve the equation for "y" :

8y = 16

Divide each side of the equation by 8

y = 2 → Your answer


There you go! I really hope this helped, if there's anything just let me know! :)


7 0
3 years ago
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Answer:

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Step-by-step explanation:

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