Greater than is your answer
Answer:
Therefore the ball strikes the ground 5.98 s after kick.
Step-by-step explanation:
Given that , a ball is kicked in the air. The height of the ball can be calculated using the equation 
where h is height in feet and t is time in second.
When the ball touches the ground then the height will be zero.
i.e h(t)=0
Therefore
Since -2≠0 then 
[The solution of a quadratic equation ax²+bx+c=0 is
here a=8, b=-32 and c=-95]
![\Rightarrow t =\frac{-(-32)\pm\sqrt{(-32)^2-[4\times8\times(-95)]} }{2\times8}](https://tex.z-dn.net/?f=%5CRightarrow%20t%20%3D%5Cfrac%7B-%28-32%29%5Cpm%5Csqrt%7B%28-32%29%5E2-%5B4%5Ctimes8%5Ctimes%28-95%29%5D%7D%20%7D%7B2%5Ctimes8%7D)
Therefore t= 5.98 or -1.98
since time can not be negative So , t=5.98 s
Therefore the ball strikes the ground 5.98 s after kick.
9514 1404 393
Answer:
Step-by-step explanation:
To find the initial amount, put 0 where t is in the formula and do the arithmetic.
A(0) = 523(1/2)^0 = 523(1) = 523
The initial amount is 523 grams.
__
To find the amount remaining after 100 years, put 100 where t is in the formula and do the arithmetic.
A(100) = 523(1/2)^(100/30) ≈ 523(0.0992123) ≈ 52
About 52 grams will remain after 100 years.
Answer:
20.922
Step-by-step explanation:
Evaluate ln 7.2 on a calculator; the correct result is 1.974.
Multiply that by 3, obtaining 5.922.
Finally, add 15 to that result: y = 15 + 3 In 7.2 = 20.922
