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Leviafan [203]
3 years ago
8

A pair of weak earthquakes is modeled by a system of inequalities. One earthquake occurred roughly 20 km east and 14 km north of

the center of Columbia, NC. The quake could be felt from 25 km away. A couple days later, another earthquake occurred 8 km west and 3 km north of the center of Columbia and could be felt from 14 km away. If Columbia is located at (0, 0) on a coordinate grid, the system of inequalities represents this scenario.
StartLayout Enlarged left-brace first row (x minus 20) squared + (y minus 14) squared less-than-or-equal-to 625 second row (x + 8) squared + (y minus 3) squared less-than-or-equal-to 196 EndLayout

Which location relative to Columbia felt both earthquakes?

4 km west and 12 km south
6 km west and 4 km north
2 km east and 10 km north
6 km east and 8 km north
Mathematics
2 answers:
AfilCa [17]3 years ago
5 0

Answer:

2 km east and 10 km north

Step-by-step explanation:

I did the activity and got the right answer.

sladkih [1.3K]3 years ago
4 0

Answer:

2 km east and 10 km north

Step-by-step explanation:

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3 years ago
-3x − 5 = 16<br> What would x = ?
kari74 [83]

Answer:

Step-by-step explanation:

-3x=16+5

-3x=21

x=21/-3

x= -7

7 0
3 years ago
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suter [353]

Answer:

the second one :)

Step-by-step explanation:

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3 years ago
How do find the area of a sector​
Anna007 [38]

Answer:

To do this you must first determine what fraction of the circle is represented by the central angle 30°. Since there are 360° in a full circle, you can find the fraction of a circle by simplifying . The sector represents of the circle. To find the arc length, you now need to find the circumference of the entire circle.

Step-by-step explanation:

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2 years ago
Please help with this question!! I need serious help!!
asambeis [7]

Answer:

<h2>The circumference is multipled by 4.</h2>

Step-by-step explanation:

The formula of an area of a circle"

A=\pi r^2

The formula of a circumference of a circle:

C=2\pi r

The area multipled by 16:

16A=16\pi r^2\\\\16A=\pi(4^2r^2)\\\\16A=\pi(4r)^2

The radius has increased fourfold, therefore:

C'=2\pi(4r)=4(2\pi r)=4C

The circumference is multipled by 4.

You can calculate the area and check the circumference:

r=11.6\ in\\\\A=\pi(11.6)^2=132.56\pi\\\\16A=(16)(134.56\pi)=2152.96\pi\ in^2

Calculate the radius:

\pi r^2=2152.96\pi             <em>divide both sides by π</em>

r^2=2152.96\to r=\sqrt{2152.96}\\\\r=46.4\ in

Calculate the circumference of both circles:

r=11.6\ in\\\\C=2\pi(11.6)=23.2\pi\ in

r=46.4\ in\\\\C'=2\pi(46.4)=92.8\pi\ in

\dfrac{C'}{C}=\dfrac{92.8\pi}{23.2\pi}=4\to C'=4C

5 0
3 years ago
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