A pair of weak earthquakes is modeled by a system of inequalities. One earthquake occurred roughly 20 km east and 14 km north of
2 answers:
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Inverse works in this way:
y = 1/9x + 2,
you should swap the places of x and y and find y again, in this case it will be
x = 1/9y + 2 => x-2 = 1/9y => (x-2) * 9y = 1 => 9y = 1/(x-2)
and finally we got y =
y = 1/9x + 2,
you should swap the places of x and y and find y again, in this case it will be
x = 1/9y + 2 => x-2 = 1/9y => (x-2) * 9y = 1 => 9y = 1/(x-2)
and finally we got y =
Answer:
∠ QPR = 64.5°
Step-by-step explanation:
The chord- chord angle QPR is half the sum of the arcs intercepted by the angle and its vertical angle, then
∠ QPR = (QR + ST ) =
(98 + 31)° = 0.5 × 129° = 64.5°
if events X and Y are independent, then for intersection we multiply the probability
P(Y∩X) = P(Y) * P(X)
We know that
Now we replace P(Y) * P(X) for P(Y∩X)
Cancel out P(X)
So
Like that
Now we replace P(X) * P(Y) for P(X∩Y)
Cancel out P(Y)
So
P(Y | X) = P(Y) and P(X | Y) = P(X) are true
Answer:
The surface area of square pyramid is 953.64 cm² .
Step-by-step explanation:
Given as for a square pyramid :
The height of pyramid = l = 15 cm
The base of square pyramid = x = 18 cm
Now,
The surface area of square Pyramid =
or , The surface area of square Pyramid =
Or, The surface area of square Pyramid =
Or, The surface area of square Pyramid = 324 + 36 ×
or, The surface area of square Pyramid = 324 + 36 × 17.49
Or , The surface area of square Pyramid = 324 + 629.64 = 953.64 cm²
Hence The surface area of square pyramid is 953.64 cm² . Answer