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kozerog [31]
3 years ago
13

Help please!!!!! Which of the following is the equation of a linr that passes through the points. (1,6) and (2,1) help!!!!

Mathematics
1 answer:
Tom [10]3 years ago
3 0
B. because the slope is negative 5 so it can't be a or d. the y-interept can't be one because it is 11.
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Ill mark you brainlist plz help if you put something random I will report you!
Yuri [45]

Answer:

y=-3/2x+4

Step-by-step explanation:

The slope or m is -3/2 and the y-intercept or b is 4.

Hope this helped :)

6 0
3 years ago
Simplify the cube root in simplest radical form.<br> 9x374<br> Please help
algol [13]

Answer:

D. xy\sqrt[3]{9y}

Step-by-step explanation:

\sqrt[3]{9x^3y^4}

\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}

The \sqrt[3]{x^3} cancels out to become x:

\sqrt[3]{9}x\sqrt[3]{y^4}

Split the y^4=y*y^3

\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}

\sqrt[3]{y^3} =y

xy\sqrt[3]{9} \sqrt[3]{y}

Put the cube root of y and cube root of 9 together:

xy\sqrt[3]{9y}

6 0
3 years ago
Can someone please help me I’m stuck
olga_2 [115]

Answer:

25

Step-by-step explanation:

You have to do base x height divided by 2

50/2

8 0
3 years ago
Can someone please help me?? Im not quite sure how to get this answer.
nekit [7.7K]

Answer:

C. 54π + 20.25√3 cm²

Step-by-step explanation:

The shaded area can be split into two areas: a sector and an isosceles triangle.

Area of a sector is:

A = (θ/360°) πr²

where θ is the central angle and r is the radius.

Area of an isosceles triangle can be found with SAS formula:

A = ½ ab sin θ

where a and b are two sides of a triangle and θ is the angle between them.

In this case, r = a = b = 9 cm.  The central angle of the sector is 240°, and the vertex angle of the triangle is 120°.  Therefore, the total area is:

A = (240°/360°) π (9 cm)² + ½ (9 cm) (9 cm) sin 120°

A = 54π + 20.25√3 cm²

5 0
3 years ago
HELP ASAP <br> H(x)=-6x+8<br> G(x)=10-2x<br><br> H(G(x))
galben [10]

<u>Answer:</u>

H(G(x)) = 12x - 52

<u>Step-by-step explanation:</u>

We are given the following two functions:

H ( x ) = - 6 x + 8

G ( x ) = 1 0 - 2 x

And we are to find the value of H(G(x)).

For that, we will apply the function of H on the function of G.

H(G(x))=H(10-2x)

H ( G ( x ) ) = - 6 ( 1 0 - 2 x ) + 8

H(G(x))=-60+12x+8

H(G(x)) = 12x - 52

7 0
3 years ago
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