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lana66690 [7]
3 years ago
10

T^2 - 12w ÷ xWho can help me here?

Mathematics
1 answer:
Daniel [21]3 years ago
5 0
T^2-12w/x I think that’s the answer
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NUMBER 4 PLZ ONLY HAVE 5 MINUTES TO ANSWER OR I FAIL!!!!!!
erastovalidia [21]
Too bad lol potatos looking as s s s
7 0
3 years ago
The rectangular prism shown is made up of unit cubes. Each unit cube has a length of one inch, a width of one inch, and a height
algol13

Answer:

cube" (and any subsequent words) was ignored because we limit queries to 32 words.

3 0
3 years ago
How do you find the perpendicular bisector of a triangle? How do you find an equation of that segment?
Aleksandr-060686 [28]

You can find the perpendicular bisector of a line segment, but
there's no such thing as the perpendicular bisector of a triangle.

What does it mean to be perpendicular to a triangle ?

What does it mean to bisect a triangle ?

6 0
3 years ago
Which operation results in an expression equivalent to ? 23y^4 - 6y^3 + 35y^2 - 20y
Tom [10]

Answer:

D. P + Q

Explanation:

Given:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7)

Required:

Determine which operation will give an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

SOLUTION:

Perform each operation given to see which of them gives an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

Q - P:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7)

Q - P = (5y² - 4y)(3y² + 7) - (8y⁴ + 6y³ + 8y)

(5y²(3y² + 7) -4y(3y² + 7)) - (8y⁴ + 6y³ + 8y)

(15y⁴ + 35y² - 12y³ - 28y) - (8y⁴ + 6y³ + 8y)

Open parentheses

15y⁴ + 35y² - 12y³ - 28y - 8y⁴ - 6y³ - 8y

Collect like terms

15y⁴ - 8y⁴ - 12y³ - 6y³ + 35y² - 28y - 8y

7y⁴ - 18y³ + 35y² - 36y

Therefore, P - Q does not give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

PQ:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

PQ = (8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y)

=(8y⁴(15y⁴ + 35y² - 12y³ - 28y) +6y³(8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y) +8y(8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y))

= 120y⁸ . . . . .

Note: You don't need to perform this operation further anymore. It would definitely not give us the equivalent expression we are looking for. The degree of the leading term (120y⁸) is way too greater than the degree of the leading term (23y⁴) of the equivalent expression we are looking for.

Thus, PQ cannot give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

P - Q:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

P - Q = (8y⁴ + 6y³ + 8y) - (15y⁴ + 35y² - 12y³ - 28y)

Open parentheses

8y⁴ + 6y³ + 8y - 15y⁴ - 35y² + 12y³ + 28y

Collect like terms

8y⁴ - 15y⁴ + 6y³ + 12y³ - 35y² + 8y + 28y

-7y⁴ + 18y³ - 35y² + 36y

Therefore, P - Q cannot give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

P + Q:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

P + Q = (8y⁴ + 6y³ + 8y) + (15y⁴ + 35y² - 12y³ - 28y)

Open parentheses

8y⁴ + 6y³ + 8y + 15y⁴ + 35y² - 12y³ - 28y

Collect like terms

8y⁴ + 15y⁴ + 6y³ - 12y³ + 35y² + 8y - 28y

23y³ - 6y³ + 35y² - 20y

Therefore, P + Q will result in an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

The answer is D.

7 0
3 years ago
A lunch menu has a 4-piece lunch special which consists of a sandwich, soup, dessert and drink. They offer the following choices
ryzh [129]

Answer:

There are 160 possible 4-piece lunch special meal.

Step-by-step explanation:

The lunch menu has a 4-piece lunch special which consists of a sandwich, soup, dessert and drink.

The available options for the sandwiches, soups, desserts and drinks are:

Sandwich: chicken, cheese and tomato, tuna, ham and lettuce, turkey

Soup: tomato, chicken noodle, vegetable

Dessert: ice-cream, piece of cake

Drink: tea, coffee, Coke, Sprite

So, the number of options are:

n (Sandwich) = n (A) = 5

n (Soup) = n (B) = 4

n (Dessert) = n (C) = 2

n (Drink) = n (D) = 4

There are 5 ways to select a sandwich, 4 ways to select a soup, 2 ways to select a dessert and 4 ways to select a drink.

The total number of possible 4-piece lunch special is:

Total number of 4-piece lunch special = n (A) × n (B) × n (C) × n (D)

                                                                =5\times4\times2\times4\\=160\\

Thus, there are 160 possible 4-piece lunch special meal.

8 0
3 years ago
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