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Kipish [7]
3 years ago
9

Identify tje scale factor that was used to graph W' X' Y'​

Mathematics
1 answer:
lubasha [3.4K]3 years ago
4 0

Answer:

its 2/3

Step-by-step explanation:

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8. © Assessment An old building has
Pani-rosa [81]

Answer:

51

Step-by-step explanation:

big windows 48

small windows 12

broken windnows9

unbroken windows= 48+12-9= 51

unbroken 51 windows

7 0
3 years ago
A boy saves 80p a day, How much does it take him to save $40
laiz [17]

Answer:

50 Days

Step-by-step explanation:

I'm not sure what the unit "p" is, but I believe it is pennies so. $40/0.80 gives you 50 which is the amount of days it would take for you to get to $40 if you receive 80 cents a day

8 0
2 years ago
A racquetball club charges $10 for a one-month trial membership. After the trail month, the regular membership fee is $12 per mo
Furkat [3]
Membership is discounted $2 for first month
c=cost of one month
d=discount=$2
x=# of months
xc - 2= total cost
x for 1 month is 1, c is always 12, -2 is constant
1 x(12) - 2=10 for first month
8 months
8c -2=total cost for 8 months
8 x 12 - 2= 94 for 8 months

5 0
3 years ago
Someone please help me I suck @ simplifying thank you
dsp73

To solve this question, you would need to find the common denominator among the 2 fractions. In this case it would be

72.

Then multiply numbers to both of the fractions to get to the bottom number in both fractions equaling 72.

40/72 + 27/72 =67/72.

Try to reduce to lowest terms by dividing a common number from both of them if possible.





5 0
3 years ago
Read 2 more answers
Find a polynomial function of degree 3 with 2, i, -i as zeros.
sergiy2304 [10]

Answer:

p(x)= x^3-2x^2+x-2

Step-by-step explanation:

Here we are given that a polynomial has zeros as 2 , i and -i . We need to find out the cubic polynomial . In general we know that if \alpha , \ \beta \ \& \ \gamma are the zeros of the cubic polynomial , then ,

\sf \longrightarrow p(x)= (x -\alpha )(x-\beta)(x-\gamma)

Here in place of the Greek letters , substitute 2,i and -i , we get ,

\sf\longrightarrow p(x)= (x -2 )(x-i)(x+i)

Now multiply (x-i) and (x+i ) using the identity (a+b)(a-b)=a² - b² , we have ,

\sf  \longrightarrow p(x)= (x-2)\{ x^2 - (i)^2\}

Simplify using i = √-1 ,

\sf \longrightarrow p(x)= (x-2)( x^2 + 1 )

Multiply by distribution ,

\sf \longrightarrow p(x)= x(x^2+1) -2(x^2+1)

Simplify by opening the brackets ,

\sf\longrightarrow p(x)= x^3+x-2x^2-2

Rearrange ,

\sf\longrightarrow \underline{\boxed{\blue{\sf p(x)= x^3-2x^2+x-2}}}

4 0
2 years ago
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