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ikadub [295]
2 years ago
8

Scarlett mowed 12 lawns in 3 hours. What was her rate of mowing in hours per lawn?

Mathematics
1 answer:
Marrrta [24]2 years ago
7 0

Answer:

4 lawns per hour

Step-by-step explanation:

;)

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A listing for a home for sale is shown as follows: "3/2/2 house for sale. Price
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I believe C. Because it provides a more meaningful explanation
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5% of is 36<br> A. 72<br> B. 720<br> C. 7.2<br> D. 72.0
Shtirlitz [24]

Answer:

b. 720

Step-by-step explanation:

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find the area and perimeter using the lengthy and with step by step I will give 40 points please answer right number 6,7,9,10,11
N76 [4]

Answer:

6. 16 meters^2, 16 meters

7. 100 milimieters^2, 40 milimeters

9. 56 centimeters^2, 30 centimeters

10. 49 inches^2, 28 inches

11. 9 meters^2, 12 meters

12. 72 yards^2, 36 yards

Step-by-step explanation:

s is for a square

A=s^2

P=4s

l+w is for a rectangle

A=lw

P=2l+2w

6. A=4^2

A= 16 meters^2

P=4*4

P= 16 meters

7. A=10^2

A=100 milimieters^2

P=4*10

P= 40 milimeters

9. A=8*7

A= 56 centimeters^2

P=2(8)+2(7)

P=30 centimeters

10. A=7^2

A=49 inches^2

P=4*7

P=28 inches

11. A= 3^2

A=9 meters^2

P=4*3

P= 12 meters

12.

A=12*6

A=72 yards^2

P= 2(12)+2(6)

P= 36 yards

Let me know if you have any questions. Also, don't forget units!

4 0
3 years ago
The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time
cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

1\leq t\geq \sqrt{2}

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

h =20-5t^{2}-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height h = 15m  

Put height value in equation 1

15 =20-5t^{2}

5t^{2} =20-15

5t^{2} =5

t^{2} =1

t =\pm1

We know that the time is always positive, therefore t=1

when the stuntman is 10m above the ground.

height h = 10m  

Put height value in equation 1

10 =20-5t^{2}

5t^{2} =20-10

5t^{2} =10

t^{2} =\frac{10}{5}

t^{2} =2

t=\pm\sqrt{2}

t=\sqrt{2}

Therefore ,time interval of camera film him is 1\leq t\geq \sqrt{2}

7 0
3 years ago
Ummm Hey,I don't know the answer for this question,when I solve the problem my answer always 6 but the real answer is 2 so I nee
kramer

umm ok then its 2...

4 0
3 years ago
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