For the points in the parabola, we have:
- A = (1, 0)
- B = (3, 0)
- P = (0, 3)
- Q = (2, -1).
<h3>
How to identify the points on the parabola?</h3>
Here we have the quadratic equation:
y = (x - 1)*(x - 3)
First, we want the coordinates of A and B, which are the two zeros of the parabola.
Because it is already factorized, we know that the zeros are at x = 1 and x = 3, so the coordinates of A and B are:
A = (1, 0)
B = (3, 0).
Then point P is the y-intercept, to get it, we need to evaluate in x = 0.
y = (0 - 1)*(0 - 3) = (-1)*(-3) = 3
Then we have:
P = (0, 3)
Finally, point Q is the vertex. The x-value of the vertex is in the middle between the two zeros, so the vertex is at x = 2.
And the y-value of the vertex is:
y = (2 - 1)*(2 - 3) = 1*(-1) = -1
So we have:
Q = (2, -1).
If you want to learn more about quadratic equations:
brainly.com/question/1214333
#SPJ1
Answer:
y= 3x^2 y= 3^x
1. 3. 3
2. 12. 9
Step-by-step explanation:
3(1)^1
3
3^1
3
3(2)^2
3(4)
12
3^2
9
Answer: it’s a decimal 9.5
Hope this helped!
Answer:
2
Step-by-step explanation:
Lines 2 and four r perpendicular I think
