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dsp73
2 years ago
7

Graph the lines by finding the points of intersection with the axes (intercepts):

Mathematics
1 answer:
saul85 [17]2 years ago
3 0

The equation is in slope-intercept form, so you can read the equation to find the y-intercept is (0, -1).

Since the slope is -1/2, the graph goes <em>up</em> 1 unit for each 2 units to the <em>left</em>. The x-axis is up 1 unit from the y-intercept, so the x-intercept is 2 units to the left of x=0, at (-2, 0).

The graph is the line that goes through the points (0, -1) and (-2, 0).

_____

If you like, you can put the equation into intercept form, which shows you both the x- and y-intercepts at once. That form is ...

... x/a + y/b = 1

where <em>a</em> and <em>b</em> are the x- and y-intercepts.

If we add 1-y to the given equation, we have ...

... 1 = (-1/2)x - y

... 1 = x/(-2) + y/(-1) . . . . intercept form

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Answer:

x = 1 and x = 6

Step-by-step explanation:

x^2-7x+6=0

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x - 6 =0; x = 6

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29 7/52

Step-by-step explanation:

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2 years ago
Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and
ANEK [815]

Answer:

\frac{360000q}{359999}

Step-by-step explanation:

p = Product of all odd integers between 500 an 598. So,

p = 501 x 503 x 505 ... x 595 x 597

q = Product of all odd integers between 500 and 602. So,

q = 501 x 503 x 505 ... x 595 x 597 x 599 x 601

From the above relations, we can see that q is equal to p multiplied by 599 and 601. i.e.

q = p x 599 x 601

or,

p=\frac{q}{599 \times 601}

We need to evaluate 1p + 1q in terms of q. Using the value of p from above expression, we get:

p+q=\frac{q}{599 \times 601} + q\\\\ p+q=\frac{q+(599 \times 601q)}{599 \times 601}\\ \\ p+q=\frac{q(1+599\times601)}{599 \times 601}\\\\ p+q=\frac{360000q}{359999}

7 0
3 years ago
Help needed asap graph posted below
Aloiza [94]
Answer: D) (x+1)(x + 2)(x-3)

This is because the roots are x = -1, x = -2 and x = 3
Simply get all the numbers to each side to have 0 on the right side

x = -1 turns into x+1 = 0
x = -2 turns into x+2 = 0
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The three factors are (x+1), (x+2) and (x-3)
Which leads to (x+1)(x+2)(x-3)

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2 years ago
Given the function g(x)=x^2+3 ,evaluate (-2,y)
Karo-lina-s [1.5K]

Answer:

im not sure if this is what you're looking for but g=x^4 and the y intercept is g(0)=0

Step-by-step explanation:

3 0
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