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dsp73
2 years ago
7

Graph the lines by finding the points of intersection with the axes (intercepts):

Mathematics
1 answer:
saul85 [17]2 years ago
3 0

The equation is in slope-intercept form, so you can read the equation to find the y-intercept is (0, -1).

Since the slope is -1/2, the graph goes <em>up</em> 1 unit for each 2 units to the <em>left</em>. The x-axis is up 1 unit from the y-intercept, so the x-intercept is 2 units to the left of x=0, at (-2, 0).

The graph is the line that goes through the points (0, -1) and (-2, 0).

_____

If you like, you can put the equation into intercept form, which shows you both the x- and y-intercepts at once. That form is ...

... x/a + y/b = 1

where <em>a</em> and <em>b</em> are the x- and y-intercepts.

If we add 1-y to the given equation, we have ...

... 1 = (-1/2)x - y

... 1 = x/(-2) + y/(-1) . . . . intercept form

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if the sum of the first 60 positive integers is s, what is the sum of the first 120 integers in terms of s? a. 2s 3600 b. s^2 36
natima [27]
For the first 60 positive integers, a = 1, n = 60, l = 60.
Sn = n/2(a + l)
s = 60/2(1 + 60) = 30(61)

For the next 60 positive integer, a = 61, n = 60, l = 120
Sum = 60/2(61 + 120) = 30(61 + 120) = 30(61) + 30(120) = s + 3600

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Picking a purple marble from a jar with 10 green and 10 purple marbles
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9 purple 10 green

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3 years ago
Read 2 more answers
An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref
hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}

So the cost of laying pipe under water with this distance is

800000\sqrt{(3 - d)^2 + 4}

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

800000\sqrt{(3 - d)^2 + 4} + 400000d

We can find the minimum value of this by taking the 1st derivative and set it to 0

800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0

We can move the first term over to the right hand side and divide both sides by 400000

1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}

\sqrt{(3 - d)^2 + 4} = 6 - 2d

From here we can square up both sides

(3 - d)^2 + 4 = (6 - 2d)^2

9 - 6d + d^2 + 4 = 36 - 24d + 4d^2

3d^2-18d+27 = 0

d^2 - 6d + 9 = 0

(d - 3)^2 = 0

d -3 = 0

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0
3 years ago
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