Graph the lines by finding the points of intersection with the axes (intercepts):
1 answer:
The equation is in slope-intercept form, so you can read the equation to find the y-intercept is (0, -1).
Since the slope is -1/2, the graph goes <em>up</em> 1 unit for each 2 units to the <em>left</em>. The x-axis is up 1 unit from the y-intercept, so the x-intercept is 2 units to the left of x=0, at (-2, 0).
The graph is the line that goes through the points (0, -1) and (-2, 0).
_____
If you like, you can put the equation into intercept form, which shows you both the x- and y-intercepts at once. That form is ...
... x/a + y/b = 1
where <em>a</em> and <em>b</em> are the x- and y-intercepts.
If we add 1-y to the given equation, we have ...
... 1 = (-1/2)x - y
... 1 = x/(-2) + y/(-1) . . . . intercept form
You might be interested in
Answer: The value of g(x) is x+3.
Step-by-step explanation:
Since we have given that
Here,
We need to find the value of g(x):
Hence, the value of g(x) is x+3.
bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.
le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.
Answer:
See Image below:)
Step-by-step explanation:
You can use the app photo math, you just take a picture of the question and it shows you the steps.
