Question

I need help asap:

Answer 1

Answer:

79.4° to the nearest tenth of a degree

Step-by-step explanation:

You are trying to find the angle opposite the side of length 27.

Let the length of that  side be c and a and b be the lengths of the other two sides and let C be the measure of the angle you are looking for

Using the law of cosines

$c = \sqrt{a^{2} + b^{2} - 2abcos C}$

$27 = \sqrt{19^{2} + 23^{2} - 2(19)(23)cosC}$

$27^{2} = 19^{2} + 23^{2} - 2(19)(23)cosC$

729 = 361 + 529 - 874cosC

729 = 890 - 874cosC

-161 = -874cosC

-161/-874 = cosC

.1842105.... = cosC

C = arccos .1842105.... = 79.4° to the nearest tenth of a degree