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LuckyWell [14K]
3 years ago
8

What is 1/5 of 11????????????

Mathematics
1 answer:
Helga [31]3 years ago
7 0
Multiply 1/5 by 11 to get 2.2, to check, multiply 2.2 by 5. The answer though, is 2.2.
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Cries In didn’t pay attention in class in my lower grades
seraphim [82]
Answer:

a. 32

b. 48

Step-by-step explanation:

Forty percent of the 80 birds were robins.

a. How many of the birds were robins?

b. How many of the birds were not robins?
___________________
Forty percent of the 80 birds that were robins = 40%/100%

To find how many of the birds were robins, use part/whole = part/whole

40%/100% = ?/80

This will tell us how many exact robins were there

To solve, multiply 80 by 40 and then divide all by 100

80 x 40 ÷ 100 = 32

so 32 of the birds were robins

now for b since 32 of the birds were robins out of 80 birds, subtract 32 from 80.

80 - 32 = 48
4 0
3 years ago
Line segment AB has endpoints A(0, 3) and B(2, 2). What is the midpoint of
natali 33 [55]

Answer:

The options doesn't match or the question is wrong but the answer is (1,2.5)

Step-by-step explanation:

x_{m}=\frac{0+2}{2}=1\\y_{m}=\frac{3+2}{2}=2.5

3 0
2 years ago
Plz help well mark brainliest if you are correct!!…
erik [133]

Answer:

A. y<-3

Step-by-step explanation:

6 0
2 years ago
What is the correct factorization of<br> 5(x + 2) – 3x(x + 2)?
ryzh [129]
(5x + 10) - (3x^2 + 6x)
5 0
3 years ago
Calcular x en: los datos q faltan
Taya2010 [7]
Answer:

x = 13

Step-by-step explanation:

No se exactamente como decir esto porque yo ayudo la majoria de los usuario en ingles pero hay que usar un método para describir a x

Un método que se llama Pythagorean theorem

Pythagorean theorem: a^2 + b^2 = c^2 donde a^2 = 5 b^2 = 12 y c^2 = x

Entonces…

5^2 + 12^2 = c^2

Nota: podemos ver que esto esta bien porque el sum de los dos lados suma el mas largo.

Ahora

25 + 144 = c^2

c^2 = 169

Pero eso no puede ser la respuesta porque no tiene sentido a que x sea un lado que mide 169 entonces tenemos que usar sqrt rt

sqrt rt de 169 = 13

x = 13
4 0
3 years ago
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