Not sure what your question is but if you are learning the order of operations you can use the phrase "Please Excuse My Dear Aunt Sally"....
Parentheses
Exponents
Multiplication from left to right
Division from left to right
Addition from left to right
Subtraction from left to right
Hope this help :)
        
             
        
        
        
The correct answer is:
 <span>
The graph shifts 5 units right
Explanation:
Below is the graph attached of both the equations:
Red line: Represents f(x) = </span><span>2x + 2.
Blue line: Represents g(x) = 2x - 3.
As you can see in the graph that g(x) is shifted 5 units right to f(x).
If you move towards right by 1 unit, you have to subtract 1 from f(x) until you reach g(x) like:
2x + 2 - 1 = 2x + 1 (1 unit)
</span>2x + 1 - 1 = 2x (1 unit)
2x - 1 = 2x - 1 (1 unit)
2x - 1 -1 = 2x - 2 (1 unit)
2x -2 - 1 = 2x -3 (1 unit)
Total 5 units.
Hence the correct answer is 
t<span>
he graph shifts 5 units right.</span>
 
        
                    
             
        
        
        
Given:
Cost to build a bookshelf = $20
Cost to build a table = $45
Amount available to spend = $600
Let x =  number of bookshelves built.
Let y =  number of tables built.
The total number of bookshelves and tables =  18. 
Therefore
x + y = 18.
 That is,
 y = 18 - x                    (1)
The total amount available to build x bookshelves and y tables = $600. Therefore
20x + 45y = 600
That is (dividing through by 5),
4x + 9y = 120            (2)
Substitute (1) into (2).
4x + 9(18 - x) = 120
4x + 162 - 9x = 120
-5x = -42
  x = 8.4
From (1),obtain
 y = 18 - 8.4 = 9.6
Because we cannot have fractional bookshelves and tables, we shall test values of x=8, 9 and y=9,10 for profit
Note: The profit is $60 per bookshelf and $100 per table.
If x = 8, then y = 18-8 = 10.
The profit = 8*60 + 10*100 =  $1480
If x = 9, then y = 18-9 = 9.
The profit = 9*60 + 9*100 = $1440
The choice of 8 bookshelves and 10 tables is more profitable.
Answer: 8 bookshelves and 10 tables.
        
             
        
        
        
C temp. pH and regulatory molecules