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Liono4ka [1.6K]
3 years ago
13

PLZ HELP!!!!!!!!!!!!!!!

Mathematics
1 answer:
emmainna [20.7K]3 years ago
8 0

Answer:

589htuvuvfd

Step-by-step explanation:

vcvcvc

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It is a timed test plz help i will give branlyiest
bixtya [17]

Answer:

5 edges and 4 vertices

Step-by-step explanation:

4 0
3 years ago
Simplify (x - y + 1) - (x + y - 1)
andrey2020 [161]
First, distribute the minus sign across the second set. So you have:

x - y + 1 - x - y + 1

Now, we combine like terms:
x-x=0
-y-y=-2y
1+1=2

So we have -2y+2

Hope that helps.
5 0
4 years ago
Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx
shutvik [7]

\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)

Let v=x+y, so that \dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}:

\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1

Now the ODE is separable, and we have

\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx

Integrating both sides gives

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx

For the integral on the left, rewrite the integrand as

\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v

Then

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C

and so

\csc v-\cot v=x+C

\csc(x+y)-\cot(x+y)=x+C

Given that y(0)=\dfrac\pi2, we find

\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1

so that the particular solution to this IVP is

\csc(x+y)-\cot(x+y)=x+1

5 0
3 years ago
What is an ordered pair (x,y) that is a solution to x-3y=3
Alina [70]

Answer:

an ordered pair could be (9,2)

6 0
3 years ago
W-2+2w=6+5w need help
Flauer [41]
The answer is W= -4
hoped this helped
6 0
4 years ago
Read 2 more answers
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