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BaLLatris [955]
3 years ago
12

Find the area of a pizza with

Mathematics
1 answer:
Airida [17]3 years ago
8 0

Answer:

area of whole pizza = 200.96 in²

area of slice of pizza = 25.12 in²

Step-by-step explanation:

16"/2 = 8" radius

area = πr² = (3.14)(8²) = 200.96 in²

200.96 in²/8 = 25.12 in²

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slamgirl [31]
Your answer would be 63.33. ((: ❤️
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A 7-pound box of raspberries costs $26.88. What is the price per ounce?
pishuonlain [190]

Answer:

26.88/7 = $3.84 per ounce

Step-by-step explanation:

7 0
3 years ago
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There are 800 desks at Washington Middle School. The custodial staff at the school plans to inspect 6.5% of the desks every week
Talja [164]

Answer:

208 desks

Step-by-step explanation:

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7 0
3 years ago
Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

The integral itself can be evaluated by writing the root and exponent of the variable u as:   \sqrt[8]{u^3} =u^{\frac{3}{8}

Then, an antiderivative of this is: \frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}

which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

Since this this function u^{\frac{3}{8} is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}

5 0
3 years ago
Solve: 125x + 3 = 52x + 4
Norma-Jean [14]
I would say x= 1/73 thats what i got
8 0
3 years ago
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