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harina [27]
3 years ago
11

Which function has a greater y intercept?

Mathematics
1 answer:
Anni [7]3 years ago
8 0

Answer:

Step-by-step explanation:

The function whose graph is given has y-intercept (0, 3), whereas the function f(x) has y intercept (0, 1).  So it is the first that has the greater y intercept.

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What is the value of x in the equation 4x+8y=40 when y=0.8
GREYUIT [131]
Substitute in 0.8 for y.

4x+8y=40 \\ \\ 4x + 8(0.8) = 40 \\ \\ 4x + 6.5 = 40 \\ \\ 4x = 40 - 6.4 \\ \\ 4x = 33.6 \\ \\ x = 8.4 \\ \\

The final result is: x = 8.4.
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The table represents a function
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B

Step-by-step explanation:

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What lines are skew to AD?
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Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2
Agata [3.3K]
\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------

\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left(  \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o
8 0
3 years ago
Solve the inequality –8 < x – 14.
Ilya [14]

Answer:

x=6

Step-by-step explanation:

7 0
3 years ago
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