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enyata [817]
3 years ago
13

An arc of length 8 in. Is intersected by a central angle in a circle with a radius of 3in. What is the measure of the angle? Rou

nd to the nearest 10th
Mathematics
1 answer:
gladu [14]3 years ago
7 0

Answer:

Step-by-step explanation:

Circumference = 6π

θ = 8/3 = 2.7 radians

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Charra [1.4K]

Answer:

443.28

Step-by-step explanation:

Subtract 42.24 from 570.3 three times.

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Answer:

2n+6=20

-6 -6

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inessss [21]
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Simplify 6m plus 2m minus 5
mr Goodwill [35]

Answer:

8m-5

Step-by-step explanation:

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8m-5

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6 0
3 years ago
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A rectangular paperboard measuring 29in long and 20in wide has a semicircle cut out of it, as shown below.
katen-ka-za [31]

Here, we are required to find the area of the paper board given after the semicircle is cut out of it

Area of the paper board thatremains is 423 in²

Length = 29 in

Width = 20 in

Area of a rectangle = length × width

= 29 in × 20 in

= 580 in²

Area of a semi circle = πr²/2

π = 3.14

r = diameter / 2 = 20 in / 2 = 10 in

Area of a semi circle = πr²/2

= 3.14 × (10 in)² / 2

= 3.14 × 100 in² / 2

= 314 in²/2

= 157 in²

The semicircle is cut out of the rectangle

Find the area of the paper board that remains after the semicircle is cut out of it by subtracting the area of a semi circle from the area of a rectangle

Area of the paper board that remains = Area of a rectangle - Area of a semi circle

= 580 in² - 157 in²

= 423 in²

brainly.com/question/16994941

6 0
3 years ago
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