I’m so confused I don’t know how to subtract fractions. What is 2+2-1 2/3

Mathematics

2 answers:

Alexxandr [17]3 years ago

7 0

Answer:

its 7/3 or you could put 2 1/3

Step-by-step explanation:

malfutka [58]3 years ago

5 0

Answer:

2 $\frac{1}{3}$

Step-by-step explanation:

To subtract fractions you convert the whole numbers into fractions.

2 + 2 = 4

4 - 1 $\frac{2}{3}$

We can convert 4 to $\frac{12}{3}$ because 12 divided by 3 equals 4. We can convert

1 $\frac{2}{3}$ to $\frac{5}{3}$ because 5 divided by 3 equals 1 $\frac{2}{3}$

We can now subtract our converted fractions:

$\frac{12}{3}$ minus $\frac{5}{3}$ = $\frac{7}{3}$

So our answer is 7/3.

This simplifies to:

2 $\frac{1}{3}$

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Determine whether the series is convergent or divergent by expressing sn as a telescoping sum (as in Example 8). [infinity] 6 n2

vekshin1

Answer:

Step-by-step explanation:

given

$\sum\limits^\infty_{n=3}\frac{6}{n^2-1}=\sum\limits^\infty_{n=3}\frac{6}{(n-1)(n+1)}\\\\=\sum\limits^\infty_{n=3}\frac{6}{2}(\frac{1}{n-1}-\frac{1}{n+1})\\\\=\frac{6}{2}\sum\limits^\infty_{n=3}(\frac{1}{n-1}-\frac{1}{n+1})\\\\=3[(\frac{1}{2}-\frac{1}{4})+(\frac{1}{3}-\frac{1}{5})+(\frac{1}{4}-\frac{1}{6})+(\frac{1}{5}-\frac{1}{7})+...]\\\\=3[\frac{1}{2}+\frac{1}{3}]=3[\frac{3+2}{6}]=3[\frac{5}{6}]\\\\=\frac{15}{6}=\frac{5}{3}$