We have been given that in ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. We are asked to find the measure of angle J to nearest degree.
First of all, we will draw a triangle as shown in the attachment.
We can see from our attachment that side KL is opposite side to angle J and side JK is hypotenuse of right triangle.
We know that sine relates opposite side of right triangle to hypotenuse.


Using inverse sine or arcsin, we will get:


Upon rounding to nearest degree, we will get:

Therefore, the measure of angle J is approximately 24 degrees.
Not really sure what you mean by compare. The only thing I can think of is the y intercept is generally a good point to start from to count the rise/run
Answer:
Step-by-step explanation:
Volume = 1/3(area of triangular base)height
To find the triangular base we would use heron formula Area = square root (s-a)(s-b)(s-c)
S = (a+b+c)/2 = 2.6 + 2.6 + 2.6 )/2