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2 years ago

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Mathematics

1 answer:

Cloud [144]2 years ago

7 0

If you are asking if your work is good,thn yes,you are right

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Can someone help me on this math question its confusing ill give brainly when right!!!

notsponge [240]

$\huge\mathsf\green{ANSWER}:—$

The coefficients are:-

-4,-6

<h2>hope it would be helpful for you</h2>

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2 years ago

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Can someone help me with this question

Alex_Xolod [135]

Answer:

Yes.

Step-by-step explanation:

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2 years ago

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Twelve of the 40 cars pulled by the locomotive were tankers.

quester [9]

12 are tankesr
40 cars total
12/40
12/40=6/20=3/10

3/10=tankders
10/10-3/10=7/10
7/10=70/100=70%
70% wern't tankser

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3 years ago

For the following pair of functions, find (f+g)(x) and (f-g)(x).

ch4aika [34]

Given:

The functions are

$f(x)=4x^2+7x-5$

$g(x)=-9x^2+4x-13$

To find:

The functions $(f+g)(x)$ and $(f-g)(x)$ .

Solution:

We know that,

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=4x^2+7x-5-9x^2+4x-13$

$(f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)$

$(f+g)(x)=-5x^2+11x-18$

And,

$(f-g)(x)=f(x)-g(x)$

$(f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)$

$(f+g)(x)=4x^2+7x-5+9x^2-4x+13$

$(f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)$

$(f-g)(x)=13x^2+3x+8$

Therefore, the required functions are $(f+g)(x)=-5x^2+11x-18$

and $(f-g)(x)=13x^2+3x+8$ .

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3 years ago

A point on the rim of a wheel has a linear speed of 33 cm/s. If the radius of the wheel is 50 cm, what is the angular speed of t

Zigmanuir [339]

Answer:

The angular speed of the wheel in radians per second is 0.66.

Step-by-step explanation:

Recall the following statement:

A linear speed (v) is given by,

$v=\omega \times r$ ...... (1)

Here, $\omega$ represents the angular speed of the wheel and <em>r</em> represents the radius of the wheel.

From the given information:

Linear speed (v) = 33 cm/s

Radius of the wheel (r) = 50 cm

Now to find the angular speed in radian per second.

$33 =50 \times \omega$

Divide both sides by 50.

$0.66 rad/sec= \omega$

Hence, the angular speed of the wheel in radians per second is 0.66.

4 0

3 years ago