Answer:
I think it would be the first choice however I may be wrong
Step-by-step explanation:
Answer:
a < -
Step-by-step explanation:
Using the discriminant Δ = b² - 4ac
For a polynomial to have 2 real roots
b² - 4ac > 0
Given
p(x) = (a + 1)x² + 2ax + (a + 2)
with a = a + 1, b = 2a and c = a + 2, then
(2a)² - 4(a + 1)(a + 2) > 0 ← expand and simplify left side
4a² - 4(a² + 3a + 2) > 0
4a² - 4a² - 12a - 8 > 0
- 12a - 8 > 0 ( add 8 to both sides )
- 12a > 8
Divide both sides by - 12, reversing the symbol as a result of dividing by a negative quantity
a < , that is
a < -
I think the answer is D but plz forgive me if i'm wrong
8x > = -64
x > = -64/8
x > = -8
10x < 60
x < 60/10
x < 6
-8 < = x < 6
Answer:
A
Step-by-step explanation:
The line is going up so it is positive. That leaves A and B. By counting squares, you can see that the line is going up at a rate of 2/3. you find this by counting from where it crosses on y=-2 too y=0. And you see the y has changes two places and the x has changed 3. Or do it in the formula y(final)-y(initial)/x(final)-x(initial) so (0-(-2))/(3-0) = 2/3. So the equation must have 2/3. So the equation is A