Let
x---------> the length of the first piece
y---------> the length of the second piece
z---------> the length of the third piece
we know that
x+y+z=72 -------> equation 1
y=x+6 -----> solve for x
x=y-6 -------> equation 2
z=6+y -------> equation 3
substitute equation 2 and equation 3 in equation 1
[y-6]+y+[6+y]=72
3y=72
y=(72/3)=24 in
<u>Find the value of x</u>
x=y-6 -------> equation 2
x=24-6=18 in
<u>Find the value of z</u>
z=6+y -------> equation 3
z=6+24=30 in
therefore
<u>the answer is</u>
the length of the first piece is 18 in
the length of the second piece 24 in
the length of the third piece is 30 in
Answer:
24c
Step-by-step explanation:
I see 4 times 6c, which is,
24c
Hope this helps!!
The equation of the line can be written as:
y - 3 = 2( x + 2)
and
y - 9 = 2(x - 1)
So the answers are E and F
Hope this helps :)
Answer:
Step-by-step explanation:
Hello!
The study variable is:
X: number of passengers that rest or sleep during a flight.
The sample taken is n=9 passengers and the probability of success, that is finding a passenger that either rested or sept during the flight, is p=0.80.
I'll use the binomial tables to calculate each probability, these tables give the values of accumulated probability: P(X≤x)
a. P(6)= P(X=6)
To reach the value of selecting exactly 6 passengers you have to look for the probability accumulated until 6 and subtract the probability accumulated until the previous integer:
P(X=6)= P(X≤6)-P(X≤5)= 0.2618-0.0856= 0.1762
b. P(9)= P(X=9)
To know the probability of selecting exactly 9 passengers that either rested or slept you have to do the following:
P(X≤9) - P(X≤8)= 1 - 0.8657= 0.1343
c. P(X≥6)
To know what percentage of the probability distribution is above six, you have to subtract from the total probability -1- the cumulated probability until 6 but without including it:
P(X≥6)= 1 - P(X<6)= 1 - P(X≤5)= 1 - 0.0856= 0.9144
I hope it helps!
