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olga2289 [7]
3 years ago
14

Can someone do this for me

Mathematics
1 answer:
vodomira [7]3 years ago
4 0
10. 80,029
11. 137.4dm 1374cm 13,740mm
12. 8.5dm 85cm 850mm 
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Can someone please answer. There is one question. There's a picture. Thank you!
barxatty [35]
Hello,

the answer is D (said Al Kashi)

6 0
3 years ago
What does 5 over 100 =
Nuetrik [128]

You can identify that "5 over 100" can be written as a fraction. 5 will be the numerator and 100 will be the denominator:

\frac{5}{100}

To reduce this fraction, you need to divide the numerator and the denominator by the Greatest Common Factor (GCF) between them.

In this case, to find the GCF, you need to:

- Decompose the number into their Prime Factors:

\begin{gathered} 5=5 \\ 100=2\cdot2\cdot5\cdot5=2^2\cdot5^2 \end{gathered}

- Notice that 5 is a common factor. Then, you need to choose the one with the lowest exponent:

GCF=5

Therefore, by dividing the numerator and the denominator by 5, you get:

=\frac{1}{20}

Hence, the answer is:

=\frac{1}{20}
8 0
11 months ago
Need help please someone
Natalka [10]
19.B 20. D 21. A. 22. A
You just put in calculator make sure you click the mode button and highlight degree so it can work
8 0
3 years ago
Please help!!!!!! Algebra question!!!!!
Bad White [126]
The answer is d trust me
4 0
3 years ago
What is the y-intercept of the line perpendicular to the line y = 4/3x + 1 that includes the point (4, 1)?
Alexeev081 [22]

\bf y=\stackrel{\downarrow }{\cfrac{4}{3}}x+1\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{4}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{4}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{4}}}

so then, we know this line has a slope of -3/4 and runs through (4 , 1)

\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{1})~\hspace{10em} slope = m\implies -\cfrac{3}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-1=-\cfrac{3}{4}(x-4)\implies y-1=-\cfrac{3}{4}x+3

\bf y=-\cfrac{3}{4}x\stackrel{\downarrow }{+4}\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hfill \stackrel{\textit{y-intercept}}{(0,4)}

3 0
3 years ago
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