2 π x 3 x 7 + π x 3^2 x2= 60 π= 188
Answer:
5/36 ; 1/12 ; 2/9 ; yes
Step-by-step explanation:
Given the following :
Roll of two fair dice : green and red
Probability = (number of required outcomes / number of total possible outcomes)
(a) What is the probability of getting a sum of 6?
Number of required outcomes = 5
P(sum of 6) = 5/36
b.) What is the probability of getting a sum of 10?
Number of required outcomes = 3
P(sum of 10) = 3 / 36 = 1/12
c.) What is the probability of getting a sum of 6 or 10?
P(getting a sum of 6) + P(getting a sum of 10)
(5/36) + (1/12) = (5 + 3) / 36
= 8/36 = 2/9
The events are mutually exclusive because each event cannot occur at the same time.
The answers are in bold
The shown relative frequencies are 0.18, 0.19, and 0.21, which is pretty close to 0.19 - 0.20. From there you can tell that they are reasonably close to equal.
That means that the probailities are close to uniform and => <span>A uniform propabililty model IS a good model to represent probabilities related to the numbers generated by Claudia's calculator.
Therefore, the theoretical probability that any one number is chosen is likely 0.2.
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