It will takes Horst 12 minutes to run 15 laps
Step 1:
Calculate the measure of angle ∠ABC
![\angle DBC+\angle ABC=180(\text{ sum of angles on a straight line)}](https://tex.z-dn.net/?f=%5Cangle%20DBC%2B%5Cangle%20ABC%3D180%28%5Ctext%7B%20sum%20of%20angles%20on%20a%20straight%20line%29%7D)
![\angle ABC=65^0](https://tex.z-dn.net/?f=%5Cangle%20ABC%3D65%5E0)
![\begin{gathered} \angle DBC+\angle ABC=180 \\ \angle DBC+65^0=180^0 \\ \angle DBC=180^0-65^0 \\ \angle DBC=115^0 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cangle%20DBC%2B%5Cangle%20ABC%3D180%20%5C%5C%20%5Cangle%20DBC%2B65%5E0%3D180%5E0%20%5C%5C%20%5Cangle%20DBC%3D180%5E0-65%5E0%20%5C%5C%20%5Cangle%20DBC%3D115%5E0%20%5Cend%7Bgathered%7D)
From the triangle in the question,
![a=10\operatorname{km},c=15\operatorname{km},B=115^0](https://tex.z-dn.net/?f=a%3D10%5Coperatorname%7Bkm%7D%2Cc%3D15%5Coperatorname%7Bkm%7D%2CB%3D115%5E0)
Step 2:
Calculate the value of AB using the cosine rule below
![b^2=a^2+c^2-2\times a\times c\times\cos B](https://tex.z-dn.net/?f=b%5E2%3Da%5E2%2Bc%5E2-2%5Ctimes%20a%5Ctimes%20c%5Ctimes%5Ccos%20B)
By substituting the values, we will have
![\begin{gathered} b^2=a^2+c^2-2\times a\times c\times\cos B \\ b^2=10^2+15^2-2\times10\times15\times\cos 115^0 \\ b^2=100+225-300\times(-0.4226) \\ b^2=325+126.78 \\ b^2=451.78 \\ \text{Square root both sides} \\ \sqrt[]{b^2}=\sqrt[]{451.78} \\ b=21.26\operatorname{km} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20b%5E2%3Da%5E2%2Bc%5E2-2%5Ctimes%20a%5Ctimes%20c%5Ctimes%5Ccos%20B%20%5C%5C%20b%5E2%3D10%5E2%2B15%5E2-2%5Ctimes10%5Ctimes15%5Ctimes%5Ccos%20115%5E0%20%5C%5C%20b%5E2%3D100%2B225-300%5Ctimes%28-0.4226%29%20%5C%5C%20b%5E2%3D325%2B126.78%20%5C%5C%20b%5E2%3D451.78%20%5C%5C%20%5Ctext%7BSquare%20root%20both%20sides%7D%20%5C%5C%20%5Csqrt%5B%5D%7Bb%5E2%7D%3D%5Csqrt%5B%5D%7B451.78%7D%20%5C%5C%20b%3D21.26%5Coperatorname%7Bkm%7D%20%5Cend%7Bgathered%7D)
Hence,
The distance of point A to point C is = 21.26km
Hi there!
In order to fin the average, you need to add all the terms together and then divide the result by the number of terms :
(
) ÷ 2 = average
Now, I’m assuming that you know that in order to add fractions, both fractions must have the same denominator (bottom number in a fraction). Since these fractions do not have the same denominator, we must give them one.
To find the lowest common denominator (which will help us solve this problem), we must find out what 2 & 3 go into. Well, both numbers go into 6!
So, if the denominator is now 6, you must multiply the numerator (numbers about the “/” line in this case are both 1) by how much you multiplied its denominator by.
For 1/2, you multiplied 2 by 3 to get 6. Therefore, you must multiply the 1 by 3 aswell.
for 1/3, you multiplied 3 by 2 to get 6. Therefore, you must multiply the 1 by 2.
and now you have 3/6+2/6 since the denominators are the same, you can add the numerators normally which gives you 5/6
÷ 2 = ![\frac{5}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B12%7D)
Your answer is : ![\frac{5}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B12%7D)
There you go! I really hope this helped, if there's anything just let me know! :)
First off we have x number of students in the robotics club, 12 more in the Science club, and 84 students in total. This means:
Robotics Club = x
Science Club = (x + 12)
Total = 84
Okay, so here's the equation:
x + (x + 12) = 84 ~ Add like terms.
2x + 12 = 84 ~ Subtract 12 by both sides.
2x = 72 ~ Divide both sides by 2.
x = 36 ~ Meaning that the Robotics Club has 36 members.
At this point you can do: 84 - 36 = 48 which gives you the number of members in the Science Club, though...:
36 + (36 + 12) = 84 ~ Add the two in the parenthesis to get your answer.
36 + 48 = 84 ~ 48 is the number of Students in the Science Club.
84 = 84
In conclusion: The Science Club has 48 students.
Hope that helps. ^ ^
{-Ghostgate-}