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2 years ago

Does the ordered pair (2,1) satisfy the following system of equations?

Mathematics

1 answer:

love history [14]2 years ago

6 0

To determine the whether the ordered pair satisfies the equation:

⇒ we must plug in the values

⇒ since coordinates are (x,y) ⇒ (2,1)

⇒ there we must plug 2 into the 'x' position in the equation

⇒ and 1 into the 'y' position in the equation

Let's try the first equation:

$3x-y=5\\3(2)-1=5\\6-1=5\\5=5$

Ordered pair satisfies first equation

Let's try the second equation

$5x-2y=8\\5(2)-2(1)=8\\10-2=8\\8=8$

Ordered pair satisfies second equation

Thus ordered pair satisfies the following system of equations

Answer: Yes

Hope that helps!

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Jordan is 12 years older than Anna. The

user100 [1]

9514 1404 393

Answer:

J = [12] +A
J + A = [50]

Step-by-step explanation:

If Anna's age is represented by A, then 12 more than Anna's age will be ...

12 + A

Jason's age is said to be 12 more than Anna's age, so ...

J = 12 + A

The sum of their ages will be J + A. That is said to be 50, so ...

J + A = 50

_____

These equations can be solved by using the first to substitute for J in the second.

(12 +A) +A = 50

2A = 38 . . . . . . . . subtract 12

A = 19 . . . . . . . . . . divide by 2

J = 12 +19 = 31 . . . find Jason's age

Jason is 31; Anna is 19.

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3 years ago

Is n+4 equal to 8(n - 4)

weqwewe [10]

No, n+4=4n an 8(n-4)=32n

4 0

3 years ago

Read 2 more answers

the empire state building is 1250 feet tall. IF an object is thrown upward from the top of the building at an initial velocity o

ss7ja [257]

Answer:

Time for the object to get h(max) s = 1.1875 sec

h (max) = 1272.57 feet

Down time for the object to hit the ground = 4.25 sec

Step-by-step explanation:

The relation

h(s) = - 16*s² + 38* s + 1250 (1)

Is equivalent to the equation for vertical shot

Δh = V(i)*t - 1/2g*t² (in this case we don´t have independent term since the shot is from ground level. We can see in (1), the independent term is 1250 feet ( the height of the empire state building), the starting point of the movement.

The description of the movement is:

V(s) = V(i) - g*s ⇒ V(s) = 38 - 32*s

At h(max) V(s) = 0 38/32 = s

So the maximum height is at s = t = 1.1875 sec

The time for the object to pass for starting point is the same

t = 1.1875 sec

h(max) is

h(max) = - 16* (1.1875)² + 38 (1.1875) + 1250

h(max) = - 22,56 + 45.13 + 1250

h(max) = 1272.57 feet

Time for the object to hit the ground is

h(s) = - 1250 feet

-1250 = - 16 s² + 38*s + 1250

-16s² + 38s = 0

s ( -16s + 38 ) = 0

First solution for that second degree equation is x = 0 which we dismiss

then

( -16s + 38 ) = 0 ⇒ 16s = 38 s = 38/16

s = 2.375 sec and we have to add time between h (max) and to get to starting point ( 1. 1875 sec)

total time is = 2.375 + 1.875

Total time = 4.25 sec

4 0

3 years ago

I need to know £400 in euros and how to convert it

enot [183]

It’s around 450 euros right now - to figure this out you multiply the number of pounds by the current exchange rate ( which you can look up)

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3 years ago

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Barack walks 2 kilometers south and then x kilometers east. He ends 5 kilometers away from his starting position. Find x

amid [387]

Answer:

4.6 km

Step-by-step explanation:

-This is a Pythagorean Theorem problem where the distances walked are effectively the base and height of the imaginary right triangle thereof.

#Apply Pythagorean theorem to solve:

$b^2+h^2=H^2\\\\2^2+x^2=5^2\\\\x^2=5^2-2^2=21\\\\x=\sqrt{21}\\\\x=4.58\ km$

$\approx 4.6\ km$

Hence, the distance x is 4.6 km

7 0

3 years ago