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siniylev [52]
3 years ago
14

Find the number of ways 5 men and 4 women can be arranged in a line if the men and women must alternate.​

Mathematics
2 answers:
Tom [10]3 years ago
8 0

Answer:

man <u>women</u> man <u>women</u> man<u> women</u> man <u>women</u> man

Step-by-step explanation:

hope it helps

PolarNik [594]3 years ago
5 0

Answer:

As there are 5 men and 4 women and they have to arrange a line, they should be positiones like this to be alternated:

MAN - WOMAN- MAN - WOMAN - MAN - WOMAN - MAN - WOMAN - MAN

In the first position they can be put 5 mans, but in the third, 4, as one has been put before, and in the fifth 3, and in the seventh 2 and in the ninth one.

In the second position they can be put 4 women, then 3, then 2 and then one.

We can multiply this:

5 * 4 * 4 * 3 * 3 * 2 * 2 * 1 * 1 = 2880

There are 2880 possibilities to form a line alternating them..

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