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3 years ago

What’s the area of this trapezium

Mathematics

2 answers:

Ivanshal [37]3 years ago

6 0

Answer:

10 cm² (the answer of blue trapezium)

Step-by-step explanation:

s=((4+6)*2)/2=10

nata0808 [166]3 years ago

5 0

Step-by-step explanation:

Area of trapezium

=1/2 h(a+b)

=1/2 2(6+4)

=1/2 2.10

=1/2 20

=10cm. cm

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According to national data, 5.1% of burglaries are cleared with arrests. A new detective is assigned to six different burglaries

blagie [28]

Answer:

26.95% probability that at least one of them is cleared with an arrest

Step-by-step explanation:

For each burglary, there are only two possible outcomes. Either it is cleared, or it is not. The probability of a burglary being cleared is independent of other burglaries. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5.1% of burglaries are cleared with arrests.

This means that $p = 0.051$

A new detective is assigned to six different burglaries.

This means that $n = 6$

What is the probability that at least one of them is cleared with an arrest?

Either none are cleared, or at least one is. The sum of the probabilities of these events is 100% = 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$

Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.051)^{0}.(0.949)^{6} = 0.7305$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7305 = 0.2695$

26.95% probability that at least one of them is cleared with an arrest

8 0

3 years ago

The competitive advantage of small American factories such as Tolerance Contract Manufacturing lies in their ability to produce

Tom [10]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the complete question in the attached file.

$H_0: \sigma^{2} \leq 0.0008\\\\H_a: \sigma^{2} > 0.0008$

The testing states value is:

$\to x^2=\frac{(n-1)s^2}{\sigma^2}=32.6250$

therefor the $\rho - \ value = 0.2931$

Through out the above equation its values Doesn't rejects the H_0 value, and its sample value doesn't support the claim that although the configuration of its dependent variable has been infringed.