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BabaBlast [244]
3 years ago
15

PLZ HELP OMG!! I’ll mark Brainliest to whoever gives correct answer first!!!

Mathematics
1 answer:
azamat3 years ago
3 0

Answer:

Step-by-step explanatioThe chosen topic is not meant for use with this type of problem. Try the examples below.

2

(

x

2

−

1

)

=

16

,  

(

0

,

4

)

 

8

=

2

(

3

x

+

3

)

2

,  

(

−

1

,

3

)

x

(

x

+

4

)

=

24

,  

(

−

2

,

9

)

n:

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Solve the equation <br> -3 2/3+b = 8 1/5<br><br> B= 5 3/5<br> B= 4 4/5<br> B= 11 3/5<br> B= 11 1/5
Readme [11.4K]

Answer:

 11 13/15

Step-by-step explanation:

-3 2/3+b = 8 1/5

Add 3 2/3 to each side

-3 2/3 + 3 2/3+b = 8 1/5+ 3 2/3

b = 8 1/5 + 3 2/3

We need to get a common denominator of 15

8 1/5 = 8 3/15

3 2/3 = 3 10/15

           ----------------

             11 13/15

4 0
3 years ago
Y=-x+8 what is this can you tell me
GREYUIT [131]

Answer:

algebra

Step-by-step explanation:- x - 8.

brainliest plzzz

4 0
3 years ago
Read 2 more answers
1 1/3+2 2/3 mixed number
OleMash [197]

1\dfrac{1}{3}+2\dfrac{2}{3}=1+\dfrac{1}{3}+2+\dfrac{2}{3}=(1+2)+\left(\dfrac{1}{3}+\dfrac{2}{3}\right)=3+\dfrac{1+2}{3}\\\\=3+\dfrac{3}{3}=3+1=4

4 0
3 years ago
Read 2 more answers
Please explain how to get the answer
meriva
Q must be positive in F.

F. r squared will be positive, because any number times itself is positive, and to get a positive number for the answer, the two numbers you multiply need to be the same sign. If r squared is positive, q must be too. 

G. q does not have to be positive. If r is a negative number, then q can be negative. Say q=-2 and r=-3. -2-(-3) changes to -2+3, which equals 1.

H. Again, q can be negative if r is negative (two negative numbers multiplied together equals a positive answer.

J. q can be negative because even a negative number turns positive when squared.

Hope this helped you. :)

8 0
3 years ago
Integral 1+cos8x/tan2x-cot2x
UkoKoshka [18]
I believe it's<span> 8cos(x)⁸ - 16cos(x)⁶ + 10cos(x)⁴ - 2cos(x)².

</span>8cosx^8 - 16cosx^6+10cosx^4-2cosx^2<span>

Alternately, you can write [</span><span><span>1 / (tan(2x) - cot(2x))] + [cos(8x) / (tan(2x) - cot(2x))].

</span></span>\dfrac{1}{tan(2x)-cot(2x)}+ \dfrac{cos(8x)}{tan(2x)-cot(2x)}<span><span>
</span></span>
5 0
3 years ago
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