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pantera1 [17]
3 years ago
9

You want $5000 4 years from nowfor a down payment for a car. How much money must be deposited monetly into an account earning 4.

2% compounded monthly to achieve this goal?
Mathematics
1 answer:
timama [110]3 years ago
8 0

Answer:

$95.5090 must be deposited monthly

Step-by-step explanation:

From the information given:

The annual interest rate (r) = 4.2% = 0.042

Let assume that an amount Y is deposited, then after one month, it will increase to:

Y ( 1+ \dfrac{0.042}{12})

The total amount after 4 years will be:

= Y ( 1+ \dfrac{0.042}{12})^{48}+Y ( 1+ \dfrac{0.042}{12})^{47} +Y ( 1+ \dfrac{0.042}{12})^{46} +...+ Y ( 1+ \dfrac{0.042}{12})

= Y ( 1.0035)^{48}+Y ( 1.0035)^{47} +Y( 1.0035)^{46} +...+ Y( 1.0035)

Using the sum of a geometric progression:

= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{(1.0035-1)}

= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{0.0035}

The above amount is then equal to $5000

i.e

= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{0.0035} = 5000

Y =  \dfrac{5000\times 0.0035}{(1.0035)(1.0035^{48}-1)} \\ \\  \mathbf{Y = \$95.5090}

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The check-cashing store also makes one-month add-on interest loans at 7.8 percent discount interest per week. Thus if you borrow
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Answer:

APR = 416%

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Step-by-step explanation:

Given:

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and, EAR ( Effective Annual Rate ) = ( 1 + r )ⁿ - 1

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5 0
3 years ago
Life Expectancies In a study of the life expectancy of people in a certain geographic region, the mean age at death was years an
Sphinxa [80]

Answer:

The probability that the mean life expectancy of the sample is less than X years is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean life expectancy, \sigma is the standard deviation and n is the size of the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

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Sample of size n:

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hjlf

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C: 2^12 is the answer

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the expression is 16^3=4069 and 2^12=4069 so 2^12 is equivalent to 16^3

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