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2 years ago

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a The function f(x) = |x - 3| can be used to determine how far a number is away from the number 3 on the number line. Find and i

nterpret the given function values and determine an appropriate domain for the function.

1 answer:

jasenka [17]2 years ago

7 0

Answer:

Please add the given function values. Or add an image.

Step-by-step explanation:

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The line segment, AB has a point C as its midpoint. If A is at (2,2) and C is at (5,4) what are the coordinates of the endpoint

Alecsey [184]

Answer:

( 8 , 6 )

Step-by-step explanation:

A = ( 2 , 2 ) and C = ( 5 , 4 )

→ Form an equation

$\frac{2+x}{2} =5$ and $\frac{2+y}{2}=4$

→ Now solve them

2 + x = 10 and 2 + y = 6

→ Simply find the values

x = 8 and y = 6

5 0

2 years ago

Read 2 more answers

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

<u><em>Question 1 a. i) Find the value of x.</em></u>

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

<u><em>Question 1a ii) Find the volume of the frustrum</em></u>

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

<u><em>Question 1b. Calculate the volume of the bin</em></u>

<u>i) Upper frustrum</u>

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

<u>ii) Lower frustrum</u>

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

<u>iii) Add the volume of the two frustrums</u>

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

2 years ago

What is the equation of the one that passes through the point (-4,-3)and has a slope of 5?

Reptile [31]

Y+3=5(X+4)
Y+3=5x+20
Y=5x+17

6 0

2 years ago

What is the value of x in the equation 5x+3 - 4x?<br> O -3<br> O -1/3<br> O 1/3<br> O 3

Alina [70]

The answer would be 3

6 0

2 years ago

Please help me with this!

TEA [102]

Answer:

y=2x+3

Step-by-step explanation:

you should see how to get from one number to the next.

I noticed by multiplying an input by 2 then adding 3 I reach my output.

I would use this for each input to find that it would equal my output every time I used the rule

5 0

2 years ago