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BartSMP [9]
3 years ago
12

The sum of two rational numbers will always be?

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
4 0
The sum of two rational numbers will always be rational. A rational number is a number that can be expressed in the form a/b with b ≠ 0. So, if we can prove that the sum of two rational numbers has a denominator, we have proven this statement. Since any rational number can be written as a/b, we can write sum of two rational numbers as a/b + c/d. We can make this ad+bc/bd. Since we proved that the sum of two rational numbers has a denominator, we also prove that their sum is rational. 
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Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match the system of equations with their so
allochka39001 [22]

Answer:

Part 1) solution {(-5,8),(3,0)} ----> y+12=x^{2}+x and x+y=3

Part 2) No solutions ----> y-15=x^{2}+4x and x-y=1

Part 3) solution [(-2,5),(3,-5)] ---> y+5=x^{2}-3x and 2x+y=1

Part 4) No solutions ---> y-6=x^{2}-3x and x+2y=2

Part 5) solution [(2,3),(8,9)] --->y-17=x^{2}-9x and -x+y=1

Part 6) solution [(-2,3),(7,-6)] --->y-15=-x^{2}+4x and x+y=1

Step-by-step explanation:

Part 1) we have

y+12=x^{2}+x ----> equation A

x+y=3 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-5,8) and (3,0)  

see the attached figure N 1

Part 2) we have

y-15=x^{2}+4x ----> equation A

x-y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs  

see the attached figure N 2

Part 3) we have

y+5=x^{2}-3x ----> equation A

2x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,5) and (3,-5)  

see the attached figure N 3

Part 4) we have

y-6=x^{2}-3x ----> equation A

x+2y=2 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs    

see the attached figure N 4

Part 5) we have

y-17=x^{2}-9x ----> equation A

-x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (2,3) and (8,9)  

see the attached figure N 5

Part 6) we have

y-15=-x^{2}+4x ----> equation A

x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,3) and (7,-6)  

see the attached figure N 6

5 0
3 years ago
Martin charges $10 for every 5 bags of leaves he rakes. Last weekend he raked 24 bags of leaves. How much money did he earn?
julsineya [31]
Martin charged $10 for every 5 bags
10/5 = 2
Martin charges $2 per bag
He raked 24 bags of leaves
24 x 2 = 48

Martin earned $48 dollars

hope this helps
8 0
3 years ago
It’s x+8 at the bottom but if you solve this please give me a step by step so I know how to solve it, thank you!!♥️
OLga [1]

Answer:

x=4.

Step-by-step explanation:

Let's solve your equation step-by-step.

5/15=x/ x+8

Step 1: Cross-multiply.

5/15=x/ x+8

5*(x+8)=x*(15)

5x+40=15x

Step 2: Subtract 15x from both sides.

5x+40−15x=15x−15x

−10x+40=0

Step 3: Subtract 40 from both sides.

−10x+40−40=0−40

−10x=−40

Step 4: Divide both sides by -10.

−10x−10=−40−10

Then your answer will be x=4.

6 0
3 years ago
A cargo grain leaves Chicago at noon travelling west at 120 km/h. At 2 pm, a passenger train leaves Chicago travelling east at 3
AfilCa [17]

Answer:

a) The trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) At that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

Step-by-step explanation:

a) First, we need to find the distance traveled by the cargo train in the two hours before the passenger train leaves Chicago:

x_{1} = v_{1}t_{1} = 120 km/h*2h = 240 km                    

Now, we can find the time when the trains will be 1520 km apart:

1520 km = (x_{1} + 240 km) + x_{2}      

Where 1 is for the cargo train and 2 is for the passenger train.

1520 km = (v_{1}*t_{1} + 240 km) + v_{2}t_{2}      

Since we need to calculate the time when the trains are 1520 km apart, t₁ = t₂, so:

1520 km = (v_{1}*t + 240 km) + v_{2}t              

t = \frac{1520 km - 240 km}{120 km/h + 360 km/h} = 2.667h

For the cargo train, it will be 1520 km apart from the passenger train at:

t_{1} = 12 pm + 2 h + 40 min = 2:40 pm

And for a passenger train, it will be 1520 km apart from the cargo train at:

t_{2} = 2 pm + 2 h + 40 min = 4:40 pm  

Hence, the trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.  

b) The distance traveled by both trains is given by:

x_{1} = v_{1}*t + 240 km = 120 km/h*2.667 h + 240 km = 560.04 km    

x_{2} = v_{2}*t = 360 km/h*2.667 h = 960.12 km    

Therefore, at that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

I hope it helps you!        

5 0
2 years ago
Olhe a imagem e responda
matrenka [14]

Answer:

i cant see the attachment

8 0
3 years ago
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