The y values need to be on the top so it would be -2-8 over -4-3 so the answer would be 10/7
Answer:
RV = 15, ∠ VUR = 48°
Step-by-step explanation:
The diagonals of a rectangle are congruent , so
RT = SU , that is
5x - 10 = 4x - 2 ( subtract 4x from both sides )
x - 10 = - 2 ( add 10 to both sides )
x = 8
Then
RT = 5x - 10 = 5(8) - 10 = 40 - 10 = 30
The diagonals bisect each other , then
RV = 0.5 × 30 = 15
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∠ RVU = ∠ svt = 84° ( vertical angles )
RV = UV ( diagonals are congruent and bisect each other )
Then Δ RVU is isosceles with base angles congruent , then
∠ VUR = 
= 
= 48°
Answer:
The answer is a
Step-by-step explanation:
The distance from the near end of the runway to the plane, divided by the altitude is the tangent of (90 degrees minus the angle of depression). Let "d1" be the distance to the near end of the runway, and "d2" be the distance to the far end of the runway. Let "a" be the altitude of the plane.
d1/a = tan(90 - 31)
d1 = a*tan(90 - 31)
d2/a = tan(90 - 23)
d2 = a*tan(90 - 23)
runway length = d2 - d1 = a*(tan(67) - tan(59))
length = 1800*(.6916) = 1245m = 1.2km
the answer is "a"
you will have 10 if im mistaken it is 5 i hope this is kinda helpful im only in 6th grade sorry if it is wrong
Answer:
Step-by-step explanation:
No it’s makes more than it so no
