We need to find the 8 th term nth term is given as <span><span>an</span>=<span>a1</span>+(n−1)d</span>
n=8, d =-4 (common difference) <span><span>a8</span>=<span>a1</span>+(8−1)×d</span>
<span><span>a8</span>=1+7×(−4<span>)</span></span>
I hoped this helped or something
That looks great! But say you chose number 2. You could say you organized it by multiplying single packs by the pieces of packs.
Other ways are m<1, YFP and m<F.
The angle is an acute angle because it is less than a right angle (less than 90 degrees).
To determine the amount of water in the first 8 beakers, you will subtract the 19 ml that are in the 9th beaker from the total to see how much water was actually put into the first 8 beakers.
91 ml - 19 ml = 72 ml.
The 72 ml are divided evenly between 8 beakers.
72/8 = 9 ml
There would be 9 ml of water in each of the first 8 beakers.
