Try this option:
1. the required surface area consists of: A=A₁+A₂+A₃, where
2. A₁=pi*r*l - the surface of the cone:
pi=3.14; r=4/2=2 cm; l=sqrt(6²+2²)=2√10≈6.33 (cm);
A₁=3.14*2*6.33=39.74 (cm²).
3. A₂=a²-pi*r² - the surface of the top plane:
A₂=36-3.14*4=23.43 (cm²).
4. A₃=5*a² - the surface of the five planes of the given cube:
A₃=5*6²=180 (cm²).
5. the required area:
A=39.74+23.43+180=243.17 (cm²).
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<u>Answer: 243.17</u>
Its an acute or an obtuse triangle
Answer:
V=4/3 π r ^3 is the answer
Answer:
2x+5
Step-by-step explanation:
Okay so lets first factor 2x^2+15x+25
2*25=50
10+5=15
10*5=15
(x+10/2)(x+5/2)
=(x+5)(2x+5)
we know that the width is x+5 so that means the length has to be 2x+5
