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FrozenT [24]
2 years ago
11

A swimming pool is 20 feet wide and 40 feet long. If it is surrounded by a walkway of square tiles, each is 1 foot by 1 foot, ho

w much area do the pool and walkway cover?
Mathematics
1 answer:
Lena [83]2 years ago
5 0

Answer:

124 tiles

Step-by-step explanation:

2(20+40)

2(60)

120+4=124

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Consider a bag containing five red marbles, three green ones, one transparent one, three yellow ones, and three orange ones How
Novay_Z [31]

Answer: 56

Step-by-step explanation:

Given : Number of red marbles = 5

Number of green marbles = 3

Number of yellow marbles = 3

Number of  orange marbles = 3

Number of red and green marbles = 5+3=8

Now the possible number of sets (combinations) of five marbles are there in which all of them red or green will be :-

^8C_5=\dfrac{8!}{5!(8-5)!}=\dfrac{8\times7\times6\times5!}{5!3!}=56

Hence, the number of sets of five marbles in which all of them red or green=56

4 0
3 years ago
How can the Pythagorean Identity be used to find sin θ, cos θ, or tan θ and the quadrant location of the angle?
Archy [21]

First lets see the pythagorean identities

sin^2 \Theta + cos^2 \Theta =1

So if we have to solve for sin theta , first we move cos theta to left side and then take square root to both sides, that is

sin^2 \Theta = 1-cos^2 \Theta => sin \theta = \pm \sqrt{1-cos^2 \Theta}

Now we need to check the sign of sin theta

First we have to remember the sign of sin, cos , tan in the quadrants. In first quadrant , all are positive. In second quadrant, only sin and cosine are positive. In third quadrant , only tan and cot are positive and in the last quadrant , only cos and sec are positive.

So if theta is in second quadrant, then we have to positive sign but if theta is in third or fourth quadrant, then we have to use negative sign .

5 0
3 years ago
A grasshopper covered a distance of 5 yards in 9 equal hops. How many yards did the grasshopper travel on each hop?
andre [41]

Answer:

a)5/9 yards=0.556yards

b)10/9 yards=1.11 yards

Step-by-step explanation:

for the part a

To solve this exercise we must divide the total distance traveled by the grasshopper (5 yards) by the number of jumps that were made (9).

d=\frac{5}{9}

if you use the calculator you will realize that the value is 0.55yards

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knowing the distance traveled in a jump, we multiply this value by two to find out how much is the distance traveled in 2 jumps

d=\frac{2x5}{9} =\frac{10}{9}

if you use the calculator you will realize that the value is 1.11 yards

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3 years ago
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Kisachek [45]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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barxatty [35]

Answer:

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Step-by-step explanation:

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