Answer: 120 ways
Step-by-step explanation:
Let's label the routes a, b, c, d, and e. The goal is to come up with as many unique permutations as possible.
1 route: a=1. one factorial (1!) =1*1=1
2 routes: ab, ba=2. 2!=1*2=2
3 routes: abc, acb, bac, bca, cab, cba=6. 3!=1*2*3=6
4 routes: 4!=1*2*3*4=24
5 routes: 5!=1*2*3*4*5=120 ways
Presumably, the coin tosses are independent of one another, so
But if the coin flips are not independent, then we can't really say anything about this probability without any more information about how the flips are related...
I would go with either NIST or SIKG. I put SIKG because the abbreviation for mass is kg and you r look for the SI unit of mass and then the SI stands for International System of units. So when you put both SI And KG (kilograms=mass) it makes SIKG.
This is probably not right but I tried.
Good Luck!
X=6 because 6 x 6 x 6 = 216
Y = 5(x+4)-6
<span>x = 5(y+4)-6 </span>
<span>x = 5y +20 - 6 </span>
<span>x= 5y +14 </span>
<span>5y = x-14 </span>
<span>y = (x-14)/5 </span>
<span>
when x = 19, y = (19-14)/5 </span>
<span>y = 5/5 </span>
<span>y=1
In short, Your Answer would be Option 2
Hope this helps!</span>
